The molarity of a hydrochloric acid solution : 0.32 M
<h3>Further explanation </h3>
Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).
Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence
1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)
2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)
M₂=0.1 M
V₂=48 ml=0.048 L
V₁=30 ml=0.03 L

Well the glaciers can melt and add more water to the oceans/seas and some animals that live in the North Pole will have no where to go...EXAMPLE: polar bears ,penguins, walruses, etc use the glaciers. Polar bears jump onto them to get to land or if they are fighting a walrus they have more fighting ground on land than in the water,etc. (There's a lot more info I just don't know if it's the correct info but what I'm telling you right now is 90% true lol.) also some of the land land can sink like islands or peninsulas(I think)
The enthalpy energy in condensation process is negative because it releases energy
The entropy in will also decreases .
Temperature affected this change because it will now create free energy if added with this result this is the condestion process
Between atoms (one metall and one non metall) form an ionic bond(NaCl)
First convert the 112 km/hr ratio into m/s (meters per second). To do this you multiply 112 km with 1000 m/km (since there's 1000 m in one km). You get 112000 m. Then multiply 1 hr with 60 min/hr (since there's 60 min in one hr. You get 60 min, but you want seconds, so multiply 60 min with 60 s/min to get 3600 s. There you go! Your answer is the speed of 112000m/3600s, but you can simplify that to 31.11m/s (since the answer should be in ? meters per 1 second.
Also, the "100-m-distance" part of the question is just to throw you off, because one particular speed obviously stays constant over any distance. Hope that helps :)