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3 years ago

Which observation illustrates the law of conservation of mass?

2 answers:

const2013 [10]3 years ago

8 0

The conservation of mass states that the total mass of reactants present before the reaction occurs is equal to the total mass of products after the reaction. From the choices, the second choice deems fit for the description of the law.

alekssr [168]3 years ago

4 0

Answer: When 3 g of carbon reacts with 8 g of oxygen, 11 g of carbon dioxide is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$C+O_2\rightarrow CO_2$

Given: mass of carbon = 3 g

mass of oxygen = 8 g

Mass of products = Mass of carbon dioxide = 11 g

Mass or reactant = mass of carbon + mass of oxygen = 3 g + 8 g = 11g

Thus the total mass of reactants is equal to the total mass of products.

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How many times more hydroxide ions are there in a solution with a ph of 9 than in a solution with a ph of 3?

cestrela7 [59]

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3 years ago

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scoundrel [369]

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3 years ago

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3 years ago

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What is the mass percent of oxygen (0) in SO2?

vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

5 0

3 years ago

How many liters of 3.5 M solution can be made using 23 moles of LiBr *must show work to get credit*

MrMuchimi

<u>Answer:</u> 6.57 L of solution can be made.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (L)}}$ .....(1)

Given values:

Molarity of LiBr = 3.5 M

Moles of LiBr = 23 moles

Putting values in equation 1, we get:

$3.5mol/L=\frac{23mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{23mol}{3.5mol/L}=6.57L$

Hence, 6.57 L of solution can be made.

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3 years ago