The heat capacity of the silver spoon at the given temperature difference is 817.65 J.
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Heat capacity of the silver spoon</h3>
The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;
Q = mcΔθ
where;
- m is mass of the spoon
- c is specific heat capacity of silver = 0.237 J/g⁰C
- Δθ is change in temperature
Q = 50 x 0.237 x (89 - 20)
Q = 817.65 J
Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.
Learn more about heat capacity here: brainly.com/question/16559442
Intensity of electromagnetic wave is given as
![I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]](https://tex.z-dn.net/?f=I%20%3D%202%5B%5Cfrac%7BB_%7Brms%7D%5E2%7D%7B2%5Cmu_0%7D%5Ctimes%20c%5D)
given that
here we know that
now we have
now we will have
frequency of wave is given as
now the induced EMF is given as
Answer:
velocity in which the space described varies from instant to instant, either increasing or decreasing in the former case called accelerated velocity
Explanation:
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Answer:
The horizontal component is zero.
The vertical component is 
Explanation:
Given that,
The lizard climb 7m directly up on a tree.
We know that,
The horizontal component is
The vertical component is
If the lizard climb 7m directly up on a tree then,
We need to find the components
Using given data
The horizontal component of lizard is
The vertical component is
Hence, The horizontal component is zero.
The vertical component is
