If you wish, you could choose i to be in the same direction as the motion and j in perpendicular direction (upwards).
The two speeds could be expressed as vectors. The speed of the boat is merely
![1.7i+0j](https://tex.z-dn.net/?f=1.7i%2B0j)
. The speed of the climbing man, using the boat as reference, is more complicated. It is
![\frac{0.60}{\sqrt{2}}i+\frac{0.60}{\sqrt{2}}j=0.30\sqrt{2}i+0.30\sqrt{2}j](https://tex.z-dn.net/?f=%5Cfrac%7B0.60%7D%7B%5Csqrt%7B2%7D%7Di%2B%5Cfrac%7B0.60%7D%7B%5Csqrt%7B2%7D%7Dj%3D0.30%5Csqrt%7B2%7Di%2B0.30%5Csqrt%7B2%7Dj)
. Calculate the sums of the two and the speed itself.
The government should put it support in a combination of sources, as no
source in the present can fully provide all energy requirements.
Just remember
Voltage = current times resistance
current = voltage over resistance
Current = 9/3 = 3
When a motorboat passes by, a disturbance or vibration in the lake water is created which travels in all the directions. A water wave is a combination of longitudinal wave as well as transverse wave. If you are a particle of water in the lake, then you would be hit by nearby water particle which would set you in motion. you would travel up and down forming crest and trough and sideways. The energy would be transported forward, as you would collide with other particle and the wave moves forward. your position would not change. only the energy would be transported.