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3 years ago

6

spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 43.9

cm?

1 answer:

fiasKO [112]3 years ago

8 0

Answer:

F2 = 282.28N

Explanation:

F = force

E = extension

F1/E1=F2/E2
135/21 = F2/43.9
6.43 = F2/43.9
F2 = 6.43 x 43.9
F2 = 282.28N

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Part B:

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Part A:

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Part B:

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Energy Required to move= Power Required*time

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Energy Used=ΔE=8640000 -2000

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Part C:

Fraction of Mass used=Δm/m

For This first calculate fraction of energy used:

Fraction of energy=ΔE/Energy required to move

ΔE is calculated in part B

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$\frac{\triangle E}{E}=\frac{\triangle m}{2m}v^2$

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