All categories

4 years ago

Stars and planets form when dust and gas from space is pulled together by.. what?

Physics

1 answer:

NemiM [27]4 years ago

5 0

Answer:

gravity?

Explanation:

i dont have a lot of context but this is what i thought of so...

You might be interested in

The carpal bones in the hands are an example of __________.

Olenka [21]

The carpal bones in the hands are an example of __________.
Answer: gliding joints

<span>A gliding joint means a freely moving joint in which the articulations allow only gliding motions</span>

6 0

3 years ago

Read 2 more answers

Explain quantum zeno effect in one sentence

otez555 [7]

It’s a feature of quantum-mechanical systems allowing a particle's time evolution to be arrested by measuring it frequently enough with respect to some chosen measurement setting.

5 0

3 years ago

Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t

ziro4ka [17]

Answer:

(a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

Explanation:

Given that,

Rotation = 20.0 times

Time = 5.00 sec

We need to calculate the angular frequency

Using formula of angular frequency

$\omega_{i}=20\times\dfrac{2\pi}{T}$

put the value into the formula

$\omega_{i}=20\times\dfrac{2\pi}{5.00}$

$\omega_{i}=8.00\pi$

We need to calculate the angular displacement

Using formula of angular displacement

$\theta=6\times2\pi=12\pi$

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}^2-\omega_{i}^2=2\alpha\times\theta$

$0-64\pi^2=2\times12\pi\times\alpha$

$\alpha=-\dfrac{64\pi^2}{24\pi}$

$\alpha=-8.3\ rad/s^2$

Negative sign shows the opposite direction of the motion.

The acceleration is 8.3 rad/s².

We need to calculate the time

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha\times t$

$0-8\pi=-8.3t$

$t=\dfrac{8\pi}{8.3}$

$t=3.0\ sec$

The time is 3.0 sec.

Hence, (a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

4 0

3 years ago

Air at 80 kPa and 127 °C enters an adiabatic diffuser steadily at a rate of 6000 kg/h and leaves at 100 kPa. The velocity of the

Vinil7 [7]

Answer:

a) The exit temperature is 430 K

b) The inlet and exit areas are 0.0096 m² and 0.051 m²

Explanation:

a) Given:

T₁ = 127°C = 400 K

At 400 K, h₁ = 400.98 kJ/kg (ideal gas properties table)

The energy equation is:

$q-w=h_{2} -h_{1} +\frac{V_{2}^{2}-V_{1}^{2} }{2} +delta-p$

For a diffuser, w = Δp = 0

The diffuser is adiabatic, q = 0

Replacing:

$0-0=h_{2} -h_{1} +\frac{V_{2}^{2}-V_{1}^{2} }{2} +0$

Where

V₁ = 250 m/s

V₂ = 40 m/s

Replacing:

$0-0=h_{2} -400x10^{3} +\frac{40^{2}-250^{2} }{2} +0\\h_{2} =431430 J/kg=431.43kJ/kg$

Using tables, at 431.43 kJ/kg the temperature is 430 K

b) The inlet area is:

$m=\frac{P_{1} }{RT_{1} } A_{1} V_{1} \\\frac{6000}{3600} =\frac{80}{0.287*400} A_{1} *250\\A_{1} =0.0096m^{2}$

The exit area is:

$m=\frac{P_{2} }{RT_{2} } A_{2} V_{2} \\\frac{6000}{3600} =\frac{100}{0.287*430} A_{2} *40\\A_{2} =0.051m^{2}$

6 0

3 years ago

In which direction does the electric field point at a position directly north of a positive charge?

navik [9.2K]

Answer:

B. South

Explanation:

An electric field can be defined as the amount of electric force per unit charge. The direction of the electric field can be determined by the motion of a positive test charge under the electric force.

The direction of electric field is radially outward for a positive charge and radially inward for a negative charge. Thus, for the electric field points toward SOUTH at a position directly south of a positive charge.

5 0

3 years ago

Read 2 more answers