All categories

4 years ago

Stars and planets form when dust and gas from space is pulled together by.. what?

Physics

1 answer:

NemiM [27]4 years ago

5 0

Answer:

gravity?

Explanation:

i dont have a lot of context but this is what i thought of so...

You might be interested in

What total distance will a sound wave travel in air in 3.00 seconds at stp?

dimaraw [331]

At stp conditions ( $T=0^{\circ}C$ ), the speed of sound is
$v=331.2 m/s$
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
$S=vt$
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
$S=vt=(331.2 m/s)(3.00 s)=993.6 m$

4 0

3 years ago

Knowing the constant g what will the gravitational force between two masses be if the gravitational force between them is 36n an

charle [14.2K]

The gravitational force between two masses is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the two masses
r is the separation between the two masses

We see that the force is proportional to the inverse of the square of the distance: $F \sim \frac{1}{r^2}$
therefore, if the distance is tripled:
r'=3r
The force decreases by a factor 1/9:
$F \sim \frac{1}{(3r)^2}= \frac{1}{9} \frac{1}{r^2}$

Since the original force was 36 N, the new force will be
$F' = \frac{1}{9} (36 N)= 4 N$

6 0

3 years ago

susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o

prisoha [69]

Answer:

3600joules

Explanation:

formula :W=FS

W=work done (J)

F=force (N)

S=displacement moved in the direction of force (m)

200N×18m

=3600J

3 0

2 years ago

An object is placed 5.00 cm beyond the focal point of a convex lens whose focal length is 10.0 cm. If the object height is 3.0 c

Aleks04 [339]

Answer:

The height of the image is, h' = 6.0 cm

The image is erect.

Explanation:

Given data,

The object distance, u = -5 cm

The focal length of convex lens, f = 10 cm

The object height, h = 3 cm

The lens formula,

$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

$\frac{1}{10}=\frac{1}{v}-\frac{1}{-5}$

$\frac{1}{v}=\frac{1}{10}-\frac{1}{5}$

v = -10 cm

The magnification factor of lens

$m=\frac{-10}{-5}$

m = 2

$m=\frac{h'}{h}$

$h'=h\times m$

$h'=3\times 2$

h' = 6 cm

The height of the image is, h' = 6 cm

The image is erect.

4 0

3 years ago

During a total lunar eclipse, where is the Moon located?

krok68 [10]

During a total lunar eclipse, the Moon located in the umbra. The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and Moon must be aligned in a straight line. The Earth’s umbra complete covers the Moon. The earth’s umbra is about 870,000 miles wide.

5 0

3 years ago