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Sliva [168]
4 years ago
15

How can a negative ion form from an atom ?

Physics
1 answer:
azamat4 years ago
3 0
Non metal atoms gain an electron(s) from another atom which makes them become negatively charged.
They do this to acquire a stable outer shell.
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A person takes a trip, driving with a constant
podryga [215]
For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time

We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.
8 0
3 years ago
a child rides her bicycle in her level drive way. what form of energy does she possess A. Elastic B. Nuclear C. Potential D. Kin
Bad White [126]

Answer:

Kinetic Energy

Explanation:

Kinetic energy is energy due to motion.

6 0
3 years ago
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Whos 18 and a boy whos smart and plays sports i need your help<br>message me
zalisa [80]

Answer:

yes

Explanation:

6 0
3 years ago
A rotating object has an angular acceleration of α = 0 rad/s2. Which one or more of the following three statements is consistent
Murrr4er [49]

Answer:

A,B and C

Explanation:

Statement A  

At all times, angular velocity is \omega = 0\,{\rm{rad/s}  

Angular acceleration is the rate of change in angular velocity with respect to time.  

Angular velocity and angular acceleration are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

Which when re-arranged becomes  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

There’s no change in angular velocity anytime when the angular velocity is \omega = 0\,{\rm{rad/s}}

The equation can be modified as follows:  

\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero hence statement A is valid.  

Statement B  

Angular acceleration is the rate of change in angular velocity with respect to time.  

Angular velocity and angular acceleration are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

Which when re-arranged becomes  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

There’s no change in angular velocity anytime when the angular velocity is \omega = 10\,{\rm{rad/s}}.The final and initial velocities remain the same.  

The equation can be modified as follows:  

\begin{array}{c}\\\alpha = \frac{{10\,{\rm{rad/s}} - 10\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero and statement B is valid  

Statement C  

Angular velocity is defined as the change in the angular position with respect to time.  

Angular velocity and angular displacement are related by  

\theta = \omega t

Which can also be modified as:  

{\theta _{\rm{f}}} - {\theta _{\rm{i}}}

Note that the final position is {\theta _{\rm{f}}}and initial position is {\theta _{\rm{i}}}

Modifying the equation to find the angular velocity we obtain  

\omega = \frac{{{\theta _{\rm{f}}} - {\theta _{\rm{i}}}}}{t}

When the angular displacement has the same value at all times, the equation becomes  

\begin{array}{c}\\\omega = \frac{{{\theta _{\rm{i}}} - {\theta _{\rm{i}}}}}{t}\\\\ = 0\\\end{array}

The angular velocity becomes zero.  

Angular acceleration and angular velocity are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

The expression above can be rearranged as follows:  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

At all times, the angular velocity is \omega = 0\,{\rm{rad/s}} hence initial and final velocities remain the same  

We obtain  

\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero and statement C is valid.  

Therefore, statements A,B and C are consistent .

4 0
4 years ago
A shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
sweet [91]

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W

5 0
4 years ago
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