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daser333 [38]
2 years ago
12

The ratio of stories to magazines is 4 to 3, if there are 28 stories, how many magazines are there?

Mathematics
2 answers:
e-lub [12.9K]2 years ago
7 0

Ratio of stories to magazines: 4:3

There are 28 stories, so that would mean we would have to divide 28 by 4 to get the common rate.

28/4 = 7

So, now we can substitute it to solve the amount of magazines.

4 x 7 = 28

3 x 7 = 21

Thus, there are 21 magazine and the non-simplified ration of stories to magazines is 28:21.

iren [92.7K]2 years ago
6 0

How many magazines are there?

12 magazine.

Step by step explanation:

The ratio of stories to magazines is 4 to 3, if there are 28 stories, how many magazines are there?

Story: c

Magazine: r

C / R

C = 4K

R = 3k

4K + 3k = 28

7k = 28

K = 7/28

K = 4

Substituting:

C = 4X4 = 16

R = 3x4 = 12

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valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5

So, the coordinates of B is (-8,-5).

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2 years ago
In one grade of 150 students, the ratio of boys to girls is 2 : 3.
denis23 [38]

Answer:

The numbers of boys in one grade are 60 .

Step-by-step explanation:

As given

In one grade of 150 students .

The ratio of boys to girls is 2:3.

Let us assume that the scalar multiple of boys and girls be x.

Thus number of boys = 2x

Number of girls = 3x

Than the equations becomes

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2 years ago
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