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grin007 [14]
3 years ago
5

The electric force between two charged objects depends on which of the following

Physics
2 answers:
emmainna [20.7K]3 years ago
6 0
<span>The electric force between two charged objects depends on
the product of their charges and the distance between them.</span>
dimulka [17.4K]3 years ago
5 0
C.) Their charge and their separation ..........
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Which main characteristics describe weather
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Out of the four options presented in this problem, the most probable answer would be A. humidity.

Weather has many characteristics which includes, but are not limited, to air temperature, wind speed, the directions of the wind, cloud cover, the type of clouds present, amount of precipitation, the type of precipitation, and of course humidity. Although B. winds is an option, it isn't ultimately a main characteristic since some weathers doesn't involve winds too much. The humidity, however, is present in all kinds of weather. The other characteristics help in differentiating which weather to which weather.
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What happens when you break a magnet in half
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They'll still be magnets, but they'll never be able to touch each other where they were cut. 

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3 years ago
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A block of mass 0.500 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x (F
Marrrta [24]

Answer:

Part a)

x = 0.4 m

Part b)

v_i = 11.7 m/s

Part c)

Speed is more than the required speed so it will reach the top

Explanation:

Part a)

As we know that there is no frictional force while block is moving on horizontal plane

so we can use energy conservation on the block

\frac{1}{2}mv^2 = \frac{1}{2}kx^2

\frac{1}{2}0.500(12^2) = \frac{1}{2}(450)x^2

x = 0.4 m

Part b)

If the track has average frictional force of 7 N then work done by friction while block slides up is given as

W_f = -7( \pi R)

W_f = -7(\pi \times 1.00)

W_f = -22 J

work done against gravity is given as

W_g = - mg(2R)

W_g = -(0.500)(9.8)(2\times 1)

W_g = -9.8 J

Now by work energy equation we have

\frac{1}{2}mv_i^2 + W_f + W_g = \frac{1}{2}mv_f^2

\frac{1}{2}0.5(12^2) - 9.8 - 22 = \frac{1}{2}(0.5)v_f^2

v_f = 4.1 m/s

Part c)

now minimum speed required at the top is such that the normal force must be zero

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = 3.13 m/s

so here we got speed more than the required speed so it will reach the top

5 0
3 years ago
Will award brainliest and upvote if you can help answer! ​
erica [24]

Answer:

Omqnp

Explanation:

I have done this before and got it correct

7 0
3 years ago
archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
Cerrena [4.2K]
Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

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