<span>Answer:
Therefore, x component: Tcos(24°) - f = 0 y component: N + Tsin(24°) - mg = 0 The two equations I get from this are: f = Tcos(24°) N = mg - Tsin(24°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24°) = 0.47 * (mg - Tsin(24°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24°) + sin(24°) * static coefficient) Then plugging in the values... T = 283.52.
Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/</span>
Answer:
C. Decreasing the distance between the objects.
Explanation:
Gravitational force depends on mass and distance. The farther the objects are apart, the less gravitational force/pull they have.
In nuclear fission, atoms are split to release the energy. A nuclear reactor, or power plant, is a series of machines that can control nuclear fission to produce electricity. The fuel that nuclear reactors use to produce nuclear fission is pellets of the element uranium. So it would be false.
Vertical acceleration = 300 m/s²
Initial vertical velocity = 0
Time of flight = 8.0 s
Calculate the height after 8 s.
h = (1/2)*(300 m/s²)*(8.0 s)² = 9600 m
Answer: 9600 m
