A 1.0-ml volume of seawater contains about 4.0 3 10212 g of gold. the total volume of ocean water is 1.5 3 1021 l. calculate the

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A 1.0-ml volume of seawater contains about 4.0 3 10212 g of gold. the total volume of ocean water is 1.5 3 1021 l. calculate the

total amount of gold (in grams) that is present in seawater, and the worth of the gold in dollars (see problem 1.82). with so much gold out there, why hasn't someone become rich by mining gold from the ocean?

Chemistry

1 answer:

olga nikolaevna [1] · Answer 1 · 2022-04-09T19:38:00+03:00

Given the volume of water = 1.0 mL

Mass of gold = $4.0*10^{-12}g$

Total volume of sea water = $1.5 * 10^{21} L$

Mass of gold in total sea water

= $1.5 * 10^{21} L$ * $\frac{1000 mL}{1 L}$ * $\frac{4.0*10^{-12}g}{1.0 mL}$

= $6.0*10^{12}g$

1 oz gold costs $948

Worth of gold in dollars = $6.0*10^{12}g$ * $\frac{1 oz}{28.3495 g} *\frac{948 dollars}{1oz}$

= $ $2.0 * 10^{14} /1 oz$

Mining of gold from oceans is not practically possible, as gold is spread through out the ocean and processing gold from such vast oceanic waters is not economical and the extraction process is inefficient.