Answer:
The specific heat of aluminium is 0.906 J/g°C
Explanation:
Step 1: data given
Mass of aluminium = 20.0 grams
Temperature = 5.00 °C
Mass of water = 20.2 grams
Temperature of water = 90.00 °C
The final temperature = 75.00 °C
Specific heat of water = 4.184 J/g°C
Step 2: calculate the specific heat of aluminium
heat won = heat lost
Qaluminium = -Qwater
Q = m*c* ΔT
m(aluminium * c(aluminium) *ΔT(aluminium = -m(water) * c(water) *ΔT(water)
⇒with m(aluminium) = mass of aluminium = 20.0 grams
⇒with c(aluminium) = the specific heat of aluminium = TO BE DETERMINED
⇒with ΔT(aluminium) = the change of temperature = T2 - T1 = 75.00 °C - 5.00 °C = 70.00 °C
⇒with m(water) = the mass of water = 20.2 grams
⇒with c(water) = the specific heat of water = 4.184 J/g°C
⇒with ΔT(water) = T2 - T1 = 75.00°C - 90.00 °C = -15.00 °C
20.0 * c(aluminium) * 70.00 = -20.2 * 4.184 * -15.00
c(aluminium) = 0.906 J/g°C
The specific heat of aluminium is 0.906 J/g°C
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