In order to compute this, we must first take a couple of assumptions of:
1) The laboratory size so we can calculate its volume
2) The number of students working in the lab so we know the total gas produced
Let the lab be
11 m × 9 m × 6 m
The volume then computes to be:
594 m³
We know that
1 Liter is 1 dm³
1 m = 10 dm
1 m³ = 1000 dm³
Therefore, the room volume in liters is:
594,000 Liters
Let there be 30 students in the laboratory
Total gas being produced:
6 × 30
= 180 Liters
This works out to be:
0.03% of Hydrogen by volume
Therefore, there is no risk of explosion given our assumption of size and students.
Answer:
A chemical equation shows the starting compound(s)—the reactants—on the left and the final compound(s)—the products—on the right, separated by an arrow. In a balanced chemical equation, the numbers of atoms of each element and the total charge are the same on both sides of the equation.
The question is incomplete. the complete question is:
A chemistry student needs 35.0 g of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is . Calculate the volume of pentane the student should pour out.Round your answer to 3 significant digits.
Answer: The volume of pentane the student should pour out is 55.9 ml
Explanation:
Density is defined as the mass contained per unit volume.
To calculate volume of a substance, we use the equation:
We are given:
Density of pentane =
Mass of pentane = 35.0 g
Putting values in above equation, we get:
(Conversion factor: )
Hence, the volume of pentane is 55.9 ml
Answer:
prepared by mixing 20 ml of 0050 m hcl with 30 ml of 010 m ba oh 2 ... No. of milliequivalents of HCl = 2× 0.05 × 1. =1.
Explanation:
is this ?