What will be the mass of 9.95 liters of propane gas (C3H8) at STP?
1 answer:
Answer:
19.5g
Explanation:
Given parameters:
Volume of propane gas = 9.95L
Unknown:
Mass of propane gas = ?
Solution:
To solve this problem, find the number of moles first.
At STP;
22.4L of gas makes up 1 mole
9.95L of gas will have a = 0.44mole
So;
Mass of propane gas = number of moles x molar mass
Molar mass of propane = 3(12) + 8(1) = 44g/mol
Mass = 0.44 x 44 = 19.5g
You might be interested in
Answer:
a
No
b
100 mm Hg
Explanation:
From the question we are told that
The vapor pressure of CHCl3, is
The temperature of CHCl3 is
The volume of the container is
The temperature of the container is
The mass of CHCl3 is m = 0.380 g
Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as
Here M is the molar mass of CHCl3 with the value
=>
=>
Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as
Here R is the gas constant with value
So
Given that the number of moles of CHCl3 evaporated is less than the number of moles of CHCl3 initially present , then it mean s that not all the liquid evaporated
At equilibrium the temperature of CHCl3 will be equal to the pressure of air so the pressure at equilibrium is 100 mmHg