Gas, as the particles have the most energy, and thus move the most.
Answer:
Because you have to give the simplest ratio of equation. Equation I can be simplified by dividing all the coefficients by 2 to make it into equation II.
*Every equation has to be in the simplest form of coefficients.
Ratio of Equation I :
2 : 4 : 2 : 4
Ratio of Equation II :
1 : 2 : 1 : 2
The given question is incomplete. The complete question is as follows.
A solution of chloroform (
) and acetone (
) exhibits a negative deviation from Raoult's law. This result implies that:
chloroform-chloroform interactions are stronger than chloroform-acetone interactions.
chloroform-chloroform interactions are weaker than chloroform-acetone interactions.
acetone-acetone interactions are stronger than chloroform-acetone interactions.
acetone-acetone interactions are weaker than chloroform-acetone interactions
chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.
Explanation:
It is known that when the forces between the particles of the mixture are stronger than the forces between the particles in the pure liquids then negative deviations from Raoult's law are observed.
Hence, when a solution of chloroform (
) and Acetone (
) will exhibit a negative deviation from Roult's law.
Then, chloroform-chloroform interactions should be weaker than chloroform-acetone interactions and acetone-acetone interactions must be weaker than Chloroform-Acetone interactions.
thus, we can conclude that for the given situation chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.
The percent composition of the compound.
A O-18.18%, N-21.21%, H-60.60%
<h3>Further explanation</h3>
Given
6.00 grams of oxygen,
7.00 grams of nitrogen,
20.00 grams of hydrogen.
Required
The percent composition
Solution
Total mass :
= mass of O + mass of N + mass of H
= 6 + 7 + 20
= 33 g
% O = 6/33 x 100%= 18.18%
% N = 7/33 x 100%=21.21%
% H = 20/33 x 100% = 60.6 %
Answer:
B will give up two electrons to form bonds.
Explanation:
B has 12 electrons, it means that the electronic configuration of B is; 1s2 2s2 2p6 3s2. The implication of this is that B must be an element of group 2 since it has an outermost electron configuration of ns2.
The elements of group 2 form ionic bonds by loss of two electrons. This implies that B will form bonds by loss of two electrons.