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11111nata11111 [884]
3 years ago
13

Everything in outer space including stars, planets, and galaxies

Chemistry
2 answers:
rewona [7]3 years ago
8 0

Answer:

B.

Explanation:

A solar system is IN a galaxy. Its not A.

A Galaxy doesnt have other galaxies in it. Its not c

A biosphere is only referring to earth. its not D.

Therefore, it is B. A universe is everything in outer space including stars, planets, and galaxies.

slega [8]3 years ago
5 0

Answer:

Universe.

Explanation:

Biosphere is just a planet. Solar system contains planets and star. Galaxy holds multiple solar systems only. Universe hold everything, biospheres, solar systems, and galaxies. I hope this helps :D

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In which state of matter do the particles spread apart and fill all the space available to them?
xz_007 [3.2K]
Gas, as the particles have the most energy, and thus move the most.
7 0
3 years ago
Both equation I and II are balanced, but equation II is the correct way to write the balanced equation. Why do you think this is
Vladimir [108]

Answer:

Because you have to give the simplest ratio of equation. Equation I can be simplified by dividing all the coefficients by 2 to make it into equation II.

*Every equation has to be in the simplest form of coefficients.

Ratio of Equation I :

2 : 4 : 2 : 4

Ratio of Equation II :

1 : 2 : 1 : 2

5 0
3 years ago
A solution of chloroform, CHCl3, and acetone, (CH3)2CO, exhibits a negative deviation from Raoult's law. This result implies tha
Gnoma [55]

The given question is incomplete. The complete question is as follows.

A solution of chloroform (CHCl_{3}) and acetone ((CH_{3})_{2}CO) exhibits a negative deviation from Raoult's law. This result implies that:

chloroform-chloroform interactions are stronger than chloroform-acetone interactions.

chloroform-chloroform interactions are weaker than chloroform-acetone interactions.

acetone-acetone interactions are stronger than chloroform-acetone interactions.

acetone-acetone interactions are weaker than chloroform-acetone interactions

chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.

Explanation:

It is known that when the forces between the particles of the mixture are stronger than the forces between the particles in the pure liquids then negative deviations from Raoult's law are observed.

Hence, when a solution of chloroform (CHCl_{3}) and Acetone ((CH_{3})_{2}CO) will exhibit a negative deviation from Roult's law.

Then, chloroform-chloroform interactions should be weaker than chloroform-acetone interactions and acetone-acetone interactions must be weaker than Chloroform-Acetone interactions.

thus, we can conclude that for the given situation  chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.

7 0
4 years ago
A compound is made of 6.00 grams of oxygen, 7.00 grams of nitrogen, and 20.00grams of hydrogen. Find the percent composition of
xxTIMURxx [149]

The percent composition of the compound.

A O-18.18%, N-21.21%, H-60.60%

<h3>Further explanation</h3>

Given

6.00 grams of oxygen,

7.00 grams of nitrogen,

20.00 grams of hydrogen.

Required

The percent composition

Solution

Total mass :

= mass of O + mass of N + mass of H

= 6 + 7 + 20

= 33 g

% O = 6/33 x 100%= 18.18%

% N = 7/33 x 100%=21.21%

% H = 20/33 x 100% = 60.6 %

6 0
3 years ago
Question 25 pts
yawa3891 [41]

Answer:

B will give up two electrons to form bonds.

Explanation:

B has 12 electrons, it means that the electronic configuration of B is; 1s2 2s2 2p6 3s2. The implication of this is that B must be an element of group 2 since it has an outermost electron configuration of ns2.

The elements of group 2 form ionic bonds by loss of two electrons. This implies that B will form bonds by loss of two electrons.

4 0
3 years ago
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