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2 years ago

13

Please help me create an hypothesis in the, if/then format for the question Does different types of vinegar, change the time it

takes for the baking soda to die down.
ILL MAKE YOU BRAINIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2 answers:

Romashka [77]2 years ago

6 0

The answer is Yes!!!!!!!!!!!!!!

motikmotik2 years ago

4 0

Answer:

ask your mom or dad to help you

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What products would you expect from the reaction of ammonia and sulfuric acid in aqueous solution? 2nh3(aq)+h2so4(aq)→ ?

arsen [322]

From the reaction of ammonia and sulfuric acid in aqueous solution 2nh3(aq)+h2so4(aq)<span>→</span> (NH4)2SO4 + H2O will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions. It is an acid-base neutralisation reaction forming ammonium sulphate as the salt. 2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.

5 0

2 years ago

If 5.0 liters H2 (g) at STP is heated to a temperature of 985, pressure remaining constant, the new volume of the gas will be?

vlada-n [284]

Answer:

$V_2=18 \ L \ H_2$

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Charles' Law: $\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Explanation:

<u>Step 1: Define</u>

Initial Volume: 5.0 L H₂ gas

Initial Temp: 273 K

Final Temp: 985 K

Final Volume: ?

<u>Step 2: Solve for new volume</u>

Substitute: $\frac{5 \ L \ H_2}{273 \ K} =\frac{x \ L \ H_2}{985 \ K}$
Cross-multiply: $(5 \ L \ H_2)(985 \ K) = (x \ L \ H_2)(273 \ K)$
Multiply: $4925 \ L \ H_2 \cdot K = 273x \ L \ H_2 \cdot K$
Isolate <em>x</em>: $18.0403 \ L \ H_2 = x$
Rewrite: $x=18.0403 \ L \ H_2$

<u>Step 3: Check</u>

<em>We are given 2 sig figs as the smallest. Follow sig fig rules and round.</em>

<em /> $18.0403 \ L \ H_2 \approx 18 \ L \ H_2$ <em />

5 0

2 years ago

The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A

Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

$-q_{combust} = q_{water} + q_{calori}$

$q_{combust}$ = heat of combustion of benzoic acid

$q_{water}$ = heat energy released to water

$q_{calori}$ = heat energy released to the calorimeter

Therefore,

$-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})$

1.056*26.42 = [0.987*4.18 + 6.66]( $T_{f}$ - 23.32)

27.8995 = [4.12566+6.660]( $T_{f}$ - 23.32)

( $T_{f}$ - 23.32) = 27.8995/10.7857 = 2.587

$T_{f}$ = 23.32 + 2.587 = 25.907°C

4 0

3 years ago

Gabriel and his friend found a piece of metal which they want to

Dominik [7]

50/5.2 that’s the equation that you have to solve then whatever comes out yo calculator is the answer

6 0

2 years ago

Read 2 more answers

Determine the concentration of H+ ions in an aqueous solution where [OH-] =2.25 × 10^-4 M. I have 29 minutes I beg u guys pls hu

mixas84 [53]

but where Is the volume in order for us to determine the concentration. since we have moles in H+ ions

then you can say

concentration = M*1000/V

6 0

2 years ago