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Illusion [34]
3 years ago
13

Consider a process in which the entropy of a system increases by 125 J K−1 and the entropy of the surroundings decreases by 125

J K−1. Is the process spontaneous?
Chemistry
1 answer:
expeople1 [14]3 years ago
4 0

Answer : The process is not spontaneous.

Explanation :

As, we know that:

Change in entropy = Change in entropy of system + Change in entropy of surrounding

As we are given in question, the entropy of surroundings decrease by the same amount as the entropy of the system increases.

For the given reaction to be spontaneous, the total change in entropy should be positive.

Given :

Entropy change of system = +125J/K

Entropy change of surroundings = -125J/K

Total change in entropy = Entropy change of system + Entropy change of surroundings

Total change in entropy = 125 J/K + (-125 J/K)

Total change in entropy = 0

The process is at equilibrium because the entropy change is equal to zero. So, the process is not spontaneous.

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The discovery of a very early form of helium supports the big bang theory because _____.
Amiraneli [1.4K]

Answer:

The discovery of early helium supports the Big Bang Theory because helium is something that would have been a product of a large explosion. Helium is also the most proliferate element in the universe.

Explanation:

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6 0
3 years ago
Read 2 more answers
Which analogy can best be likened to the activation energy of a chemical reaction?
olganol [36]
The activation energy of a reaction is the minimum energy that must be overcome in order for the reaction to take place. One way of reaching the activation energy is by manipulating the process conditions like pressure or temperature. But the most common method is by adding an enzyme. An enzyme speeds up the rate of the reaction but does not actively take part in it.

An analogy would be pushing heavy wooden block down a slope. No matter how many people push on it, the block won't move because of friction. But if you spill oil on the floor, the block would effortlessly move down the slope. The oil here is like an enzyme in a reaction.
6 0
4 years ago
#1: At STP, how many molecules of nitrogen gas are in 22.4 L?
OLEGan [10]

At STP, 1 mol = 22.4

1 mol = 6.022 X 10^ 23

so your answer is right it is B 6.022 X 10^ 23

3 0
3 years ago
When 38.1 grams of a certain metal at a temperature of 90.0°C is added to 100.0mL of water at a temperature of 17.6°C in a perfe
MakcuM [25]

Answer:

a. qm = 627.3 J

b. qw = 627.3 J

c. C₂ = 227.4 J/kg.°C

Explanation:

a.

Since, the calorimeter is completely insulated. Therefore,

Heat Lost by Metal = Heat Gained by water

qm = qw

qm = m₁C₁ΔT₁

where,

qm = heat lost by metal = ?

m₁ = mass of water = (density)(volume) = (1000 kg/m³)(100 mL)(10⁻⁶ m³/1 mL)

m₁ = 0.1 kg

C₁ = specific heat capacity of water = 4182 J/kg.°C

ΔT₁ = Change in Temperature of Water = 19.1°C - 17.6°C = 1.5°C

Therefore,

qm = (0.1 kg)(4182 J/kg.°C)(1.5°C)

<u>qm = 627.3 J</u>

<u></u>

b.

Since,

qm = qw

<u>qw = 627.3 J</u>

<u></u>

c.

qm = m₂C₂ΔT₂

where,

m₂ = mass of metal = 38.1 g = 0.0381 kg

C₂ = specific heat capacity of metal = ?

ΔT₂ = Change in Temperature of metal = 90°C - 17.6°C = 72.4°C

Therefore,

627.3 J = (0.0381 kg)(C₂)(72.4°C)

(627.3 J)/(0.0381 kg)(72.4°C) = C₂

<u>C₂ = 227.4 J/kg.°C</u>

6 0
3 years ago
Will give brainlest if answer correct
Blababa [14]

Explanation:

I think the answer is B and A

6 0
3 years ago
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