Why do the diagonals of a square intersect at their midpoints?
1 answer:
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The equation of circle with the center at (h,k) is:
r stands for radius. Therefore r^2 = diameter or 2×radius.
The question has already given the information we need, which are:
- radius = 4
- the center at (0,8)
Since the center is (h,k) - therefore the center is at h = 0 and k = 8 making it (h,k) = (0,8).
Substitute the values in the equation:
Simplify to the simplest form
Answer
- The equation of a circle is x^2+(y-8)^2 = 16
