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I am Lyosha [343]

2 years ago

6

A criminal has escaped in a train wreck. The police believe he could have traveled no more than 7 mi in any direction from the w

reck. How many square miles must be searched

1 answer:

adelina 88 [10]2 years ago

5 0

Answer:

A = 153.94 sq mi

Step-by-step explanation:

In this scenario, we would be starting from the center point and searching the area of a square since the distance in every direction would the same 7 mi. This 7-mile distance would be our radius in this scenario. We now need to use the formula for the Area of a circle to calculate the search area. This formula is the following

A = $\pi r^{2}$

A = $\pi 7^{2}$

A = $\pi 49$

A = 153.94 sq mi

A total of 153.94 square miles must be searched.

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solniwko [45]

Step-by-step explanation:

Here we are given that , the Value of

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And we need to find the prove that ,

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We know a identity as ,

$(a-b)^3 = a^3-b^3-3ab(a-b)$

On cubing both sides of the given equation,

$(3x-2y)^3 = 9^3$

Simplify and then substitute ,

$27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729$

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3 years ago

6(m-1) = 3(3m + 2) Show all work

nordsb [41]

Answer:

$\boxed{\sf m = -4}$

Step-by-step explanation:

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2 years ago

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

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Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

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