Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical reaction is,
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 3 mole of
So, moles of
react to give
moles of
Now we have to calculate the mass of
Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation:
The given data is as follows.
= 225.5 mL,
= 45.00 mL
= 0.09988 M,
= ?
Therefore, formula to calculate final concentration will be as follows.
=
Putting the given values into the above formula as follows.
=
=
= 0.5 M
Thus, we can conclude that the final concentration of the given solution is 0.5 M.
Answer:
[See Below]
Explanation:
✦ Physical Changes:
✧ Is when the form changes, but not the chemicals in that form.
✧ An example of this would be chopping wood. It's still wood but it's a different size now. It's easier to burn it since it's smaller.
✦ Chemical Changes:
✧ Is when the chemicals inside that form change to something else entirely
✧ An example would be an egg, when you cook the egg it can turn into being scrambled or fried. But you can't eat the raw egg until the chemicals change.
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Answer:
0.677 moles
Explanation:
Take the atomic mass of K = 39.1, O =16.0, P = 31.0
no. of moles = mass / molar mass
no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)
= 0.02256 mol
From the equation, the mole ratio of KOH : K3PO4 = 3 :1,
meaning every 3 moles of KOH used, produces 1 mole of K3PO4.
So, using this ratio, let the no. of moles of KOH required to be y.
y = 0.02256 x3
y = 0.0677 mol
If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.