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2 years ago

What is the significance of carbon having four valence electrons?

Chemistry

1 answer:

Dmitry_Shevchenko [17]2 years ago

6 0

Answer:

Sorry for the late answer, but it should be A. Carbon's outermost shell can form up to 4 covalent bonds. It's one of the reasons why Carbon is considered an "essential element".

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Anyone know this I Need help

aleksandr82 [10.1K]

Answer:

which one?

Explanation:

do you need help on all?

5 0

4 years ago

Answer the following questions.

maw [93]

The mole ratio can be seen below and the volume of each precipitate is 60 mL.

A mole ratio refers to a conversion factor that compares the quantities of two chemicals in moles in a chemical laboratory experiment.

Mole ratio For 1:

= 10 mL : 50 mL
= 1 : 5 mL

Mole ratio For 2:

15 mL : 45 mL
= 1 : 3 mL

Mole ratio For 3:

20 mL : 40 mL
1 : 2 mL

Mole ratio For 4:

30 mL : 30 mL
1 mL : 1 mL

Mole ratio For 5:

40 mL : 20 mL
2 : 1 mL

Mole ratio For 6:

45 mL : 15 mL
3 : 1 mL

Mole ratio For 7:

50 mL : 10 mL
5 : 1 mL

Since the parameters from the left side of the diagram are not shown, we will assume that the volumes for each precipitate are the addition of both volumes in each column.

By doing so, we have:

(10 +50) mL = 60 mL

(15 + 45) mL = 60 mL

(20 + 40)mL = 60 mL

(30 + 30) mL = 60 mL

(40 + 20)mL = 60 mL

(45 + 15) mL = 60 mL

(50 + 10)mL = 60 mL

Learn more about mole ratio here:

brainly.com/question/19099163

7 0

3 years ago

5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time

11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of methane gas, m = 16 g/mol

Molar mass of oxygen gas,m' = 32 g/mol

By taking their ratio, we get:

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}$

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142$

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen = $d_{O_2}=\frac{1 m}{t}$

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane= $d_{CH_4}=\frac{y }{t}$

$\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142$

y = 1.4142 m

Methane gas will be able to travel 1.4142 meter in the same conditions.

8 0

3 years ago

In a laboratory experiment, after purification, 4.567 g of nickel metal was obtained by a student. The student then calculated,

DaniilM [7]

Answer:

The yield of the purification is 79.7%

Explanation:

Hi there!

5.731 g nickel metal could be produced by the student if the yield of the purification would be 100%. Instead, 4.567 g was obtained. Then, the yield of the purification can be calculated as follows:

4.567 g Ni · (100% / 5.731 g) = 79.7%

The yield of the purification is 79.7%

Have a nice day!

5 0

3 years ago

Read 2 more answers

An atom of 40 18 Ar has a nucleus that contains a total of

Cloud [144]

The correct answer is b, 18 protons

4 0

4 years ago

Read 2 more answers