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romanna [79]
2 years ago
5

Cocaine (C₁₇H₂₁O₄N) is a natural substance found in coca leaves, which have been used for centuries as a local anesthetic and st

imulant. Illegal cocaine arrives in the United States either as the pure compound or as the hydrochloride salt (C₁₇H₂₁O₄NHCL). At 25°C, the salt is very soluble in water (2.50 kg/L), but cocaine is much less so (1.70 g/L).
Chemistry
1 answer:
kondor19780726 [428]2 years ago
3 0

Cocaine is a stimulant substance obtained from the leaves of two Coca species native to South America, Erythroxylum coca and Erythroxylum novogranatense.

<h3>What is a coca?</h3>

Coca is a plant. The leaves of the coca plant are the source of cocaine, which is an illegal that is used nasally, injected, or smoked for mind-altering effects.

Cocaine is also an FDA-approved Schedule II . This means cocaine can be prescribed by a healthcare provider, but the process is strictly regulated.

<h3>What happens when you smoke coca leaves?</h3>

The smoking of coca paste causes four distinct successive phases of mental disorder: euphoria, dysphoria, hallucinosis and paranoid psychosis. It can produce severe intoxication, prolonged or relapsing psychosis and, in some cases, end of life.

Learn more about cocaine here:

<h3>brainly.com/question/944545</h3><h3 /><h3>#SPJ4</h3>
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Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4
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Answer:

\large \boxed{\text{392 u}}

Explanation:

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The formula for the freezing point depression by a nonelectrolyte is

\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}

2. Calculate the moles of solute

\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}

3. Calculate the molecular mass

\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}

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How many liters are in 7.41 x 1026 atoms of helium (He) at STP?
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Explanation: Avogadro number,N, = 6.02214076*10^23per mole —> 22.71L

—>( 7.41*10^26/N)*22.71 = 22.79*10^3 = 22,790L

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3 years ago
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