They are of the same period and are similar in some form
I believe the amount of matter in an object is it's mass
Answer: Option (a) is correct.
Explanation:
Molecules of sugar given = 
According to Avogadro's number it is known that 1 mole contains
.
Therefore, calculate the moles of sugar present in the sample as follows.
Number of moles = 
= 0.25 mol
Thus, the moles of sugar present in the sample is 0.25 mol.
Answer : The activation energy for the reaction is, 52.9 kJ/mol
Explanation :
According to the Arrhenius equation,

or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= initial temperature = 
= final temperature = 
= rate constant at
= 
= rate constant at
= 
= activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
Now put all the given values in this formula, we get:
![\log (\frac{25.0s^{-1}}{12.5s^{-1}})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{298.0K}-\frac{1}{308.0K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B25.0s%5E%7B-1%7D%7D%7B12.5s%5E%7B-1%7D%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298.0K%7D-%5Cfrac%7B1%7D%7B308.0K%7D%5D)

Therefore, the activation energy for the reaction is, 52.9 kJ/mol
Answer:
1.38 x
atoms
Explanation:
To get grams to atoms/molecules/particles we need to first convert grams > moles > atoms. This also applies in the other direction, where you have moles as that stepping stone.
Some key information we need:
Magnesium's molar mass= 24g/mol
Avogadro's Number= 6.022 x
atoms
Where there is 1 mol per 6.022 x
atoms
*This maybe be something you want to memorize.
Grams to moles using molar mass , then to atoms using avogadro's number.
55g Mg x
x
= 1.38 x
atoms