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katovenus [111]
3 years ago
11

If a leaf and a dime are dropped from the same height, what force will cause the leaf to fall more slowly?

Chemistry
1 answer:
Veronika [31]3 years ago
8 0
It's friction, but friction in air is called Air Resistance. So, that's your answer.
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Elements located in the vertical column of the periodic table are of the same ___ and have ___ chemical properties.
Firdavs [7]
They are of the same period and are similar in some form
6 0
3 years ago
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The amount of matter in an object is called _______.
Troyanec [42]
I believe the amount of matter in an object is it's mass
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3 years ago
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A sample of sugar (C12H22O11) contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?
saveliy_v [14]

Answer: Option (a) is correct.

Explanation:

Molecules of sugar given = 1.505 \times 10^{23}

According to Avogadro's number it is known that 1 mole contains 6.023 \times 10^{23}.

Therefore, calculate the moles of sugar present in the sample as follows.

   Number of moles =  \frac {1.505 \times 10^{23}}{6.023 \times 10^{23}}

           = 0.25 mol

Thus, the moles of sugar present in the sample is 0.25 mol.

6 0
3 years ago
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reaction is found to have a rate constant of 12.5 s-1 at 25.0 Celsius. When you heat the reaction up by ten degrees Celsius, the
lisabon 2012 [21]

Answer : The activation energy for the reaction is, 52.9 kJ/mol

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

T_1 = initial temperature = 25.0^oC=273+25.0=298.0K

T_2 = final temperature = 25.0^oC+10=35.0^oC=273+35.0=308.0K

K_1 = rate constant at 25.0^oC = 12.5s^{-1}

K_2 = rate constant at 35.0^oC = 2\times K_1=2\times 12.5s^{-1}=25.0s^{-1}

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

Now put all the given values in this formula, we get:

\log (\frac{25.0s^{-1}}{12.5s^{-1}})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{298.0K}-\frac{1}{308.0K}]

Ea=52903.05J/mole=52.9kJ/mol

Therefore, the activation energy for the reaction is, 52.9 kJ/mol

4 0
3 years ago
Show your work and include answer with units.<br><br> How many atoms in 55 grams of magnesium
Georgia [21]

Answer:

1.38 x 10^{24} atoms

Explanation:

To get grams to atoms/molecules/particles we need to first convert grams > moles > atoms. This also applies in the other direction, where you have moles as that stepping stone.

Some key information we need:

Magnesium's molar mass= 24g/mol

Avogadro's Number= 6.022 x 10^{23} atoms

Where there is 1 mol per 6.022 x 10^{23}  atoms

*This maybe be something you want to memorize.

Grams to moles using molar mass , then to atoms using avogadro's number.

55g Mg x \frac{1 mol}{24g/mol} x \frac{6.022 x 10^{23} atoms }{1 mol} = 1.38 x 10^{24} atoms

8 0
3 years ago
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