38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen

Question

jeka57 [31]

3 years ago

10

38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen

is the limiting reactant?
3Si + 2N2 yields Si3N4

Chemistry

1 answer:

zhuklara [117] · Answer 1 · 2022-05-03T23:08:15+03:00

3Si + 2N2 --> Si3N4 (as given)

n(Si) = m/MM = 38.25/28.085 = 1.3619 mol
n(N2) = 14.33/2*14.007 = 0.5115 mol

Therefore, N2 is limiting and Si is in excess
The molar ratio of 2N2:Si3N4 is 2:1
So, 0.0575 mol of silicon nitride is formed (dividing 0.5115 by 2)

m of silicon nitride= n*mm = 0.0575*140.283 = 8.06627... g
= 8.066g (4 significant figures)

(hopefully it is right, but double check in case i did something wrong) :)