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jeka57 [31]
3 years ago
10

38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen

is the limiting reactant?
3Si + 2N2 yields Si3N4
Chemistry
1 answer:
zhuklara [117]3 years ago
6 0
3Si + 2N2 --> Si3N4 (as given) 

n(Si) = m/MM = 38.25/28.085 = 1.3619 mol
n(N2) = 14.33/2*14.007 = 0.5115 mol

Therefore, N2 is limiting and Si is in excess 
The molar ratio of 2N2:Si3N4 is 2:1 
So, 0.0575 mol of silicon nitride is formed (dividing 0.5115 by 2) 

m of silicon nitride= n*mm = 0.0575*140.283 = 8.06627... g 
= 8.066g (4 significant figures) 

(hopefully it is right, but double check in case i did something wrong) :) 
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Jlenok [28]

Answer: It showed that all atoms contain electrons.

Explanation:

  • J.J. Thomson's experiments inside a cathode ray tube in the presence of an electric field showed that all atoms contain tiny negatively charged subatomic particles "electrons".
  • Also, Thomson's plum pudding model of the atom had negatively-charged electrons embedded within a positively-charged "soup."
  • Furthermore, Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny positively-charged nucleus.
  • Then, Rutherford proposed the nuclear model of the atom based on these results.
7 0
3 years ago
According to the law of conservation of matter, which statement about chemical reactions is true?
Yanka [14]

Atoms cannot be created or destroyed by chemical reactions. They just have a some bonds rearranged is all.


3 0
3 years ago
I need to solve for x in this equation<br><br> ln(760/630)=32/8.314(1/x-1/329.5)
Anuta_ua [19.1K]
X=0.031903 I think if you don’t know how to do this photo math would be a good thing for you
4 0
3 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

5 0
3 years ago
URGENT! Consider the following decomposition reaction of ammonium carbonate ((NH4)2CO3):
dexar [7]
<span>Using PV=nRT to find the moles and then convert back.
</span><span>4x=.8944
</span><span>solve for x then use the pressure for lets say CO2 put that into PV=nRT then solve for n then convert over.
</span>
<span>(.2236)(2)/(298*.08206) = .0183*96g/mol = 1.76g
</span>
<span>For C:

[NH3]^2[CO2][H2O] = Kp
x=0.2236 (2*.2236)^2(.2236)*(.2236)
  =0.001
</span>
6 0
3 years ago
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