All categories

3 years ago

Water is a covalent compound and doesn’t conduct electricity. With this in

Chemistry

2 answers:

Komok [63]3 years ago

7 0

Answer:

You would be electrocuted if you bathed with the hair dryer, even if the shower is with perfectly pure distilled water, because even though the distilled water is pure and does not conduct electricity, it dissolves the ions of the body, from the bathtub, from the hair dryer or any surface that is not completely clean and will conduct electricity.

Explanation:

Water does not conduct electricity, but ions dissolved in water will. Because the electric current is transported by means of ions in solution, the conductivity increases when the ion concentration increases. Then pure or distilled water would not conduct electricity. Upon contact with any surface that is not completely clean, ions dissolve and conduct electricity.

The water used to take a shower, wash or drink water, contains mineral salts that are ionized, that is to say that they are electrically charged, in addition to different ions such as calcium, magnesium, nitrites, chlorides and nitrates, which allow the passage of current.

You would be electrocuted if you bathed with the hair dryer, even if the shower is with perfectly pure distilled water, because even though the distilled water is pure and does not conduct electricity, it dissolves, as previously mentioned, the ions of the body, from the bathtub, from the hair dryer or any surface that is not completely clean and will conduct electricity.

oee [108]3 years ago

3 0

the water wants to give the electricity to you because it doesn't want any more electrons it throws them away and gives them to your body

You might be interested in

A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio

Pachacha [2.7K]

Answer:

$pK_{a}$ of HA is 6.80

Explanation:

$pK_{a}=-logK_{a}$

Acid dissociation constant ( $K_{a}$ ) of HA is represented as-

$K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$

Where species inside third bracket represents equilibrium concentrations

Now, plug in all the given equilibrium concentration into above equation-

$K_{a}=\frac{(2.00\times 10^{-4})\times (2.00\times 10^{-4})}{0.250}$

So, $K_{a}=1.6\times 10^{-7}$

Hence $pK_{a}=-log(1.6\times 10^{-7})=6.80$

6 0

2 years ago

Draw the structure of 2 methyl,but-3-ene

Maslowich

Answer:

Please find the structure attached as an image

Explanation:

Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.

- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.

- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).

N.B: In the structure attached below, the counting is from the left to right (→).

5 0

2 years ago

Which of the following is a farming method that helps reduce the effects of wind erosion?

MrMuchimi

You can reduce wind erosion by providing a protective plant cover for the soil.

4 0

3 years ago

Calculate the standard entropy of vaporization of ethanol, C2H5OH, at 285.0 K, given that the molar heat capacity at constant pr

MArishka [77]

Answer: The standard entropy of vaporization of ethanol is 0.275 J/K

Explanation:

$C_2H_5OH(l)\rightleftharpoons C_2H_5OH(g)$

Using Gibbs Helmholtz equation:

$\Delta G=\Delta H-T\Delta S$

For a phase change, the reaction remains in equilibrium, thus $\Delta G=0$

$\Delta H=T\Delta S$

Given: Temperature = 285.0 K

$\Delta H=78.3J/mol$

Putting the values in the equation:

$78.3J=285.0K\times \Delta S$

$\Delta S=0.275J/K$

Thus the standard entropy of vaporization of ethanol is 0.275 J/K

4 0

3 years ago

Compare the values of the spin quantum number for two electrons in the same orbital

Leokris [45]

If there are 2 electrons in the same orbital, the spin numbers would be different for both of these 2 electrons. One would have an up spin and the other a down spin.

3 0

3 years ago