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Natasha_Volkova [10]
3 years ago
15

Write a paragraph at least 10 sentences explaining how rocks are used today in society

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
3 0
There are many different ways to use Rocks you can’t paint them, sit on them, throw them, eat them , make crafts with them
You might be interested in
Builders and dentists must store plaster of Paris,
eimsori [14]

Answer:

547 L of water vapour

Explanation:

Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20

From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.

Molar mass of gypsum = 172 g/mol

Molar mass of H2O = 18 g/mol

Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour

i.e. 344 g of gypsum produces 54 g of H2O

2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.

Volume of water vapour produced = mass/density

Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour

Therefore 547 L of water vapour are produced

3 0
3 years ago
Na+ FeBr2 what are the products
densk [106]

Hello:


Balanced equation:


2 Na + FeBr2 = 2 NaBr + Fe


Reaction type: single replacement


Hope that helps!

8 0
4 years ago
Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve
pochemuha

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.

The balanced neutralization equation is:

NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)

  • Step 1: Calculate the reacting moles of KHP.

0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.

0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol

  • Step 2: Determine the reacting moles of NaOH.

The molar ratio of NaOH to KHP is 1:1.

1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH

  • Step 3: Calculate the molarity of NaOH.

1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.

[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Learn more about titration here: brainly.com/question/4225093

3 0
3 years ago
The key enzyme in the regulation of the citric acid cycle is:.
bixtya [17]

The key enzyme in the regulation of the citric acid cycle is citrate synthase. It functions in the mitochondria.

<h3>Citrate synthase and cellular respiration </h3>

Cellular respiration is a series of reactions that produce ATP by using the energy stores in the chemical bonds of foods.

Cellular respiration is divided into glycolysis, the citric-acid cycle and oxidative phosphorylation.

Citrate synthase is an enzyme found in the mitochondrial matrix, which is involved in the citric acid cycle.

Learn more about cellular respiration here:

brainly.com/question/2809259

3 0
3 years ago
7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0
3 years ago
Read 2 more answers
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