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The distance covered by the object between t =4 s and t = 6 s is 4 m
Explanation:
In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.
Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.
We see that we have to calculate the area of a triangle, with:
Base:
And height:
Therefore, the area is
So, the distance covered by the object is 4 m.
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The ball will take 0.45 seconds to reach the ground
<h3>How will we solve this question?</h3>We will use Newton’s laws of motion, so
H= taking height= 1m
The 3 laws of motion given by Newton are as follows:
1) Unless an unbalanced force acts upon it, an item at rest remains at rest, and an object in motion continues to move in a straight line at a constant pace.
2) An object's acceleration is influenced by its mass and the force being applied.
3) Whenever one thing applies force to another, the second object applies the opposing, equal force to the first.
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