Answer:
1 ) Distribution of mass within the ball
2 ) Height of the ramp
Explanation:
Acceleration of a rolling body down an inclined plane is given by the following formula
a = g sinθ / ( 1 + k² / R² )
k is radius of gyration , R is radius of the spherical object ,
when acceleration is more , velocity will also be more .
for objects in which masses are lying in the periphery like in hollow sphere , the value of k²/R² will be high so denominator of the expression will be high so acceleration will be less , hence velocity on reaching the bottom will be less.
On mass of the ball , velocity will not depend .
If height is increased , ball will have acceleration for greater time so velocity will be high.
On radius it will not depend because , radius r and k increases proportionately.
Answer: Light passes through the front of the eye (cornea) to the lens. The cornea and the lens help to focus the light rays onto the back of the eye (retina). The cells in the retina absorb and convert the light to electrochemical impulses which are transferred along the optic nerve and then to the brain.
Explanation:
When light rays reflect off an object and enter the eyes through the cornea (the transparent outer covering of the eye), you can then see that object. The cornea bends, or refracts, the rays that pass through the round hole of the pupil.
<em>Answer:</em>
<em>r=x+y</em>
<em>sorry if its not correct you can delete if you want.</em>
Answer:
The answer is 4th choice. Down with a speed less than v.
Explanation:
The momentum of the person and the balloon need to cancel each other out. Momentum formula of the balloon is as following:
At the moment of t=0, the person and the balloon has the 0 speed.
When the person starts to climb on a balloon, balloon need to cancel this momentum out. We know that the balloon is more heavier than the person. So balloon need to go down with the speed of less than v.
You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final² = (V)initial²+2a(dx)
Given:
a=0.500m/s²
dx=6.32 m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.51396m/s