The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?
1 answer:
The distance covered by the object between t =4 s and t = 6 s is 4 m
Explanation:
In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.
Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.
We see that we have to calculate the area of a triangle, with:
Base:
And height:
Therefore, the area is
So, the distance covered by the object is 4 m.
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<h3>602.08 N</h3>Hope this helps you
The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/.
Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.
To determine Paola's acceleration, the third equation of free fall is appropriate.
i.e =
± 2as
where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.
From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.
So that since Poala flies against gravity, then we have:
=
- 2as
0 = - 2(a x 0.201)
= 16 - 0.402a
0.402a = 16
a =
= 39.801
a = 39.80 m/
Therefore Paola's acceleration is 39.80 m/.