After the first 2 min the 20 g are only 10g, (1 half-life)
after other 2 more min 5g (2 half-lives)
after other 2 more min 2.5 g (3 half-lives)
after 2 more 1.25 g (4 haf lifes)
Ignoring the n's, there would only be one unpaired electron.
Answer:
1.80 × 10²⁴ Molecules of Sucrose
Solution:
Number of Moles and Number of Particles (molecules in given case) are related to each other as,
Moles = Number of Molecules ÷ 6.022 × 10²³
Solving for Number of Molecules,
Number of Molecules = Moles × 6.022 × 10²³
Data Given;
Moles = 3 moles
Putting values in eq,
Number of Molecules = 3 mol × 6.022 × 10²³
Number of Molecules = 1.80 × 10²⁴ Molecules
T A R G E T or T J M A X X
