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Zinaida [17]
2 years ago
8

Investigate Weathering and Erosion 1. Describe at least one part of the experimental procedure that you thought was essential to

getting good results. Did you find that certain steps in the procedure had to be followed carefully in order to get consistent results? If you wanted better results, do you think there is a step that could have been added to the procedure?
2. Discuss your thoughts on the overall lab design. Did it help you understand the concepts better, or did it raise more questions? Do you think you could have designed a better experiment? If so, explain how and then discuss it with your classmates. Share some of your knowledge with them or learn a little more about the experiment you just did.​
Chemistry
2 answers:
zvonat [6]2 years ago
4 0

Answer:

Controlling the environment is the most key procedures for getting good results.

Explanation:

The control environment for an experiment is the essential part for getting good results. In control environment, there is no or less chances of disruption

from the external environment which can cause the results of the data more acceptable. So the scientists prefers laboratory for performing experiment as compared to outer environment. So in my opinion for getting better results, the control environment is the most necessary experimental procedure.

jolli1 [7]2 years ago
3 0

Answer:

it is The control environment for an experiment is the essential part for getting good results. In control environment, there is no or less chances of infestation from the external environment which can cause the results of the data more acceptable. So the scientists prefers laboratory for performing experiment as compared to outer environment. hope this helps and make's sense

Explanation:

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When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solutio
8090 [49]

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

<u>Data:</u>

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL

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3 years ago
What is pomsis? can someone please help ​
Feliz [49]
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8 0
3 years ago
A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
3 years ago
Which types of clouds are bright white ad fluffy,sometimes forming shapes or pictures?
lawyer [7]
The answer is cumulus. 

Stratus clouds often low and sometimes confused for fog. Cirrus clouds are thin and wispy.
4 0
3 years ago
Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet
sergeinik [125]

Volume of room  = 7.2 m \times 5.8 m \times  3.9 m

= 162.864 m^{3}

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg  = 6,400 \times 1000

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone  = \frac{6,400,000 microgram}{162.864 m^{3}}

= 39296.5910 microgram per cubic meter or 3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}

Hence, concentration of acetone is equal to 4.0\times 10^{4} \mu g/m^{3}

7 0
2 years ago
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