Answer:
i will do it brainlist plz
Explanation:
the calculated value is Ea is 18.2 KJ and A is 12.27.
According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.
At 500K, K=0.02s−1
At 700K, k=0.07s −1
The Arrhenius equation can be used to calculate Ea and A.
RT=k=Ae Ea
lnk=lnA+(RT−Ea)
At 500 K,
ln0.02=lnA+500R−Ea
500R Ea (1) At 700K lnA=ln (0.02) + 500R
lnA = ln (0.07) + 700REa (2)
Adding (1) to (2)
700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.
=ln [0.02/0 .07]
Ea= 2/35×100×8.314×1.2528
Ea =18227.6J
Ea =18.2KJ
Changing the value of E an in (1),
lnA=0.02) + 500×8.314/18227.6
= (−3.9120) +4.3848
lnA=0.4728
logA=1.0889
A=antilog (1.0889)
A=12.27
Consequently, Ea is 18.2 KJ and A is 12.27.
Learn more about Arrhenius equation here-
brainly.com/question/12907018
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It will likely give up its valence electron to the other compound, forming stable octets on each of the newly formed ions. These ions have opposing charges, and tend to form strong ionic lattices. A good example of this is NaCl, which contains Na+ ions that have given up their one valence electron and Cl- ions which have accepted that electron.
Hope this helps!
Answer:
there is no image there so i do not know
Explanation:
Answer:
b. some sodium iodide will precipitate out of solution
Explanation:
We know that for salts solubility decreases as the temperature of the solution decreases. So, NaI being a salt, its solubility will surely decrease when the temperature is cooled down to 25°C from 50°C.
Thus,the undissolved sodium iodide will precipitate out of the solution.
