A majority of the 118 elements on the periodic table are classified as what?

What volume is occupied by 18.4 g oxygen at 28.0°C and a pressure of 0.998 torr? (round to sig figs)

Alexxandr [17]

Answer:

11.0 dm³

Explanation:

From the question,

Applying

PV= nRT............... Equation 1

Where P = pressure of oxygen gas, V = volume of oxygen gas, n = number of moles of oxygen, R = molar constant, T = Temperature.

make V the subeject of the equation

V = nRT/P............. Equation 2

But,

Number of mole (n) = Mass of oxygen(m)/Molar mass of oxygen(m')

n = m/m'....................... Equation 3

Substitute equation 3 into equation 2

V = mRT/Pm'............. Equation 4

Given: T = 28°C = (28+273) = 301 K, P = 0.998 torr = (0.998×0.00131579) = 1.3132 atm, m = 18.4 g

Constant: R = 0.082 atm.dm³/K.mol, m' = 32 g/mol.

Substitute these values into equation 4

V = (301×18.4×0.082)/(32×1.3132)

V = 454.1488/42.0224

V = 10.81 dm³

V = 11.0 dm³

8 0

3 years ago

Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -> BrF3(g) = –3

arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

ΔH°r = Σ Eb broken - Σ Eb formed

1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken = (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0

3 years ago

What caused the temperature of the sand to change?

Setler79 [48]

Sand is usually hot from the sun. It is hot because of the sun. if the sand were to be wet then it would take longer to change.

8 0

3 years ago

Read 2 more answers

As you have seen, ozone is formed in the upper atmosphere through the reaction:

baherus [9]

The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

Reaction of Ozone :.

O(g) + O2(g) → O3(g)

Required

the rate law equation

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For reaction

aA + bB ⇒ C + D

The rate law can be formulated:

$\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}$

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

$\tt \boxed{\bold{r=k[O][O_2]}}$

5 0

3 years ago

when 4.00 g of sulfur are combined with 4.00 g of oxygen, 8.00 g of sulfur dioxide (so2) are formed. what mass of oxygen would b

Darina [25.2K]

Answer:

6g O2

Explanation:

Mole to mole ratio:

A balanced chemical equation shows a chemical reaction while maintaining the law of conservation of mass. The coefficients of the substances are known to be very helpful in computations as they represent the equivalent amounts of moles of the species that would be participating in the reaction.

We set up the chemical equation and then find the balanced chemical expression.

S+O2→SO3

Balance

2S+3O2→2SO3

We use the following values for the variables:

mS=4.0 gm

We proceed with the solution.

mO2= 4 g S × 1 mol S/ 32 g S × 3 mol O2/ 2 mol S × 32g O/ 1 mol O2

mO2 = 6 g

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brainly.com/question/17961582?referrer=searchResults

7 0

2 years ago