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3 years ago

Calculate the mass (in ng) of 2.33 x 1020 atoms of oxygen.

Chemistry

2 answers:

Ipatiy [6.2K]3 years ago

6 0

Answer:

$6.19*10}^{6}$ g of Oxygen

Explanation:

In order to answer the question the Avogadro´s number is needed:

Avogadro´s number = $6.022*10^{23}$ $mol^{-1}$

Calculate the mass using the Avogadro´s number:

$2.33*10^{20}atomsO*\frac{1molO}{6.022*10^{23}atomsO}*\frac{16gO}{1molO}*\frac{1*10^{9}g}{1g}=6.19*10}^{6}$ g of Oxygen

Law Incorporation [45]3 years ago

4 0

Answer = 6.19 x 10^6

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When a 18.0 mL sample of a 0.308 M aqueous hydrofluoric acid solution is titrated with a 0.361 M aqueous sodium hydroxide soluti

sleet_krkn [62]

Answer:

pH = 12.8

Explanation:

HF + NaOH → F⁻ + Na⁺ + H₂O

1 mole of HF reacts with 1 mole of NaOH

Initial moles of HF and NaOH are:

HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF

NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH

That means moles of NaOH remains after reaction are:

8.303x10⁻³mol - 5.544x10⁻³mol = 2.759x10⁻³moles NaOH

Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L

Molar concentration of NaOH is

2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]

pOH = - log [OH⁻] = 1.17

As pH = 14 - pOH

pH = 12.8

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3 years ago

An astronomer is a guest speaker at your school. She states that iron is the very last product in stellar fusion. Why would she

Zarrin [17]

Iron is the very last product in stellar fusion is that; Iron has a tightly bound nucleus, and atoms larger than iron are less stable and tend to undergo nuclear fission.

The stability of an atom is dependent on the binding energy per nucleon of the atom.

The binding energy per nucleon of elements increases steadily until iron, we can see that from the curve very easily.

Beyond iron, we have exceeded the region of stable binding energy per nucleon of atoms. The atoms after iron in the curve are mostly unstable heavy nuclei.

Learn more: brainly.com/question/10095561

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2 years ago

How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)? (4 points) 2L

Keith_Richards [23]

Answer:

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Explanation:

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3 years ago

A compound with molecular formula C6H9No that has an amide functional group and does not have an alkene group

Flauer [41]

Answer:

Following are the responses to the given question:

Explanation:

$\to C_6H_9NO$

calculating the HOI:

$= \frac{2C+2+N-H-X}{2} \\\\ =\frac{2\times 6+2+1-9-0}{2}\\\\ =\frac{12-6}{2}\\\\=\frac{6}{2}\\\\=3$

So, in the above compund there are three bounds or we can say that one is double and two bound is single.

Please find the attachment file of the Function group:

In the above given conditon compound doesn't include the alkene functional group that is absense of $-C=C-$ , and compound include $-C\equiv C-$ So, please find the attached file of the structure of the compound: