What is the factored form Of 6x^2 -4x + 15x - 10
2 answers:
Answer:
(3x-2)(2x+5)
or
(2x+5)(3x-2) by commutative property
Step-by-step explanation:
Let's try factoring by grouping.
I'm going to group the first two terms together and the second two terms together.
Now I'm going to factor what I can from each pair:
Now if you look at the terms 2x(3x-2) and 5(3x-2) you should see they have a common factor of (3x-2) so we can factor that out now.
(3x-2)(2x+5)
Factoring by grouping was a successful here.
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Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
_____
A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
_____
A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.