An element's atomic number is 62. How many electrons would an atom of this element have?

Compare and contrast aldehydes, ketones and alcohols in terms of structure, physical properties and chemical properties.

Ksivusya [100]

The functional group of aldehyde is -CHO

The functional group of ketone is -CO-

The functional group of alcohol is -OH

<h2>STRUCTURES</h2><h3>ALDEHYDE</h3>

The carbonyl group is bounded to at least one hydrogen atom

<h3>KETONE</h3>

The carbonyl group is bounded to two carbon atom

<h3>ALCOHOL</h3>

Organic molecules assembled from carbon, oxygen and hydrogen.

<h2>PHYSICAL PROPERTIES</h2><h3>COLOUR</h3>

Aldehyde. alcohols and ketone are colourless

<h3>ODOURS</h3>

Alcohols are sweet smell expect glycerol

Aldehyde have unpleasant odors

ketone have pleasant odors

<h3>BOILING POINT</h3>

Alcohol , Aldehyde and Ketone have High boiling point

<h3>STATE</h3>

Alcohol, Aldehyde and Ketone are in liquid state

<h2>CHEMICAL PORPERTIES</h2><h3>OXIDATION </h3>

Alcohol oxidized to form carboxylic acid

Aldehyde oxidized to form carboxylic acid

Ketone oxidized to form carboxylic acid

Learn more about alcohol, aldehyde and ketone on

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7 0

2 years ago

25 g of NH, is mixed with 4 moles of O, in the given reaction:

FromTheMoon [43]

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

3 0

3 years ago

Read 2 more answers

Why is nucleus of an atom charged is negatively charged?

Damm [24]

Answer:

Charge is caused by a flow of electrons, since electrons are around the nucleus they can be lost or gained by atoms. When an atom gets charged, it gains a charge, that is, it gains an electron. Since electrons are negatively charged, when an atom gains one, it also becomes negatively charged.

3 0

3 years ago

a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.

Juliette [100K]

Volume = 3 cm × 3cm × 3cm
= 27 cm ³

Mass = 213 g

Density = $\frac{MASS}{VOLUME}$

= <span> $\frac{213 g}{27 cm ^{3} }$
</span>
<span> = 7.89 g / cm³

Thus answer is D.</span>

8 0

3 years ago

Read 2 more answers

. Consider the following half-reactions:

Vedmedyk [2.9K]

d. Fe(s) and Al(s)

<h3>Further explanation</h3>

In the redox reaction, it is also known

Reducing agents are substances that experience oxidation

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction

The electrodes which are easier to reduce than hydrogen (H), have E cells = +

The electrodes which are easier to oxidize than hydrogen have a sign E cell = -

So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)

The metal : d. Fe(s) and Al(s)

7 0

3 years ago