Answer:
V of Sulfur tetrafluoride is 17.2 L
Explanation:
Given data;
T = -6°C = 267K [1° C = 273 K]
n = 786 mmol of SF4 which is 0.786 mol
P = 1 atm
from ideal gas law we have
PV = nRT
where n is mole, R is gas constant, V is volume
V of Sulfur tetrafluoride is 17.2 L
Answer:
Kb = 6.22x10⁻⁷
Explanation:
Triethanolamine, C₆H₁₅O₃N, is in equilibrium with water:
C₆H₁₅O₃N(aq) + H₂O(l) ⇄ C₆H₁₅O₃NH⁺(aq) + OH⁻(aq)
Kb is defined from concentrations in equilibrium, thus:
Kb = [C₆H₁₅O₃NH⁺] [OH⁻] / [C₆H₁₅O₃N]
The equilibrium concentration of these compounds could be written as:
[C₆H₁₅O₃N] = 0.486M - X
[C₆H₁₅O₃NH⁺] = X
[OH⁻] = X
pH is -log [H⁺], thus, [H⁺] = 10^-pH = 1.820x10⁻¹¹M
Also, Kw = [OH⁻] ₓ [H⁺];
1x10⁻¹⁴ = [OH⁻] ₓ [H⁺]
1x10⁻¹⁴ = [OH⁻] ₓ [1.820x10⁻¹¹M]
5.495x10⁻⁴M = [OH⁻], that means <em>X = 5.495x10⁻⁴M</em>
Replacing in Kb formula:
Kb = [5.495x10⁻⁴M] [5.495x10⁻⁴M] / [0.486M-5.495x10⁻⁴M]
<em>Kb = 6.22x10⁻⁷</em>
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Each section would be 230 centimeters or 2.30 meters long.
<h3>Sectional division</h3>
The original wood pole is 12 meters long.
12 meters = 12 x 100 = 1200 centimeters
It is to be cut into 5 equal sections: 1200/5 = 240 centimeters
But each cut wastes 10 cm of the pole.
240 - 10 = 230 centimeters.
Thus, each section would be 230 centimeters or 2.30 meters long.
More on sectional divisions can be found here: brainly.com/question/15381501
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Answer:
Zn 3
s 1
o 4
Zn. zine
s. sulphate
o oxygen
3znso4. zine sulphateoxide
Answer:
400 ml at 20⁰C
Explanation:
VP ∝ Temp => Increasing temperature increases VP or decreasing temperature decreases VP. VP is independent of the quantity of liquid in consideration. Therefore, the sample at the lower temperature would have the lowest VP; i.e., 400-ml at 20⁰C.
