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saul85 [17]
3 years ago
15

true or false Newtons's First Law states "Acceleration depends on the mass of the object and the unbalanced force applied"

Physics
2 answers:
babunello [35]3 years ago
8 0
False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.

Nady [450]3 years ago
7 0
The answer to your question would be False. Newton's First Law actually states "a body at rest (or in motion) will remain at rest (or in motion) until acted upon by an unbalance force."
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Can you respond this two questions, please? :
Andrews [41]

Where's the diagram for question 1?

6 0
4 years ago
What is the magnification of an astronomical telescope whose objective lens has a focal length of 74 cm and whose eyepiece has a
Novay_Z [31]

Answer:

The magnification of an astronomical telescope is -30.83.

Explanation:

The expression for the magnification of an astronomical telescope is as follows;

M=-\frac{f_o}{f_e}

Here, M is the magnification of an astronomical telescope, f_e is the focal length of the eyepiece lens and f_o is the focal length of the objective lens.

It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.

Put f_o=74 cm and f_e=2.4 cm in the above expression.

M=-\frac{74}{2.4}

M=-30.83

Therefore, the magnification of an astronomical telescope is -30.83.

5 0
4 years ago
An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if
maxonik [38]
The electron is accelerated through a potential difference of \Delta V=780 V, so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
\frac{1}{2}mv^2 =  e \Delta V
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
\Delta V is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s


Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evB=m \frac{v^2}{r}
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T
3 0
4 years ago
What quantity is represented by a unit called a newton (N)?
zavuch27 [327]

\textsf {C. Force}

\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}

5 0
2 years ago
Which of these does NOT result in the acceleration of an object?
Zanzabum

I guess the correct answer is the first one.

6 0
3 years ago
Read 2 more answers
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