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4 years ago

13

Convert 540 cg= ____ Hg

1 answer:

Sidana [21]4 years ago

8 0

540 centigram is 0.054 hectograms

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A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an a

Ksju [112]

Answer:

17. NADH has a molar extinction coefficient of 6200 M2 cm at 340 nm. Calculate the molar concentration of NADH required to obtain an absorbance of 0.1 at 340 nm in a 1-cm path length cuvette. 18. A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an appropriate solvent blank. Tyrosine is known to be the only chromophore present in the sample that has significant absorption at 274 nm. Calculate the molar concentration of tyrosine in the sample.

Explanation:

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3 years ago

Once water has been heated to its boiling point, additional heating will not raise its temperature. what happens to this additio

solong [7]

A. Energy was used to change phase of water from liquid to gas (evaporation). it is radiated back into the atmosphere from the stove.
This is because water evaperates after reaching it's boiling point.

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3 years ago

Read 2 more answers

A 50 kg bobsled slides down an ice track starting (at zero initial speed) from the top of a(n) 184 m high hill. The acceleration

Feliz [49]

Answer:

Explanation:

Given

mass of ice $m=50\ kg$

Height of hill $h=184\ m$

Neglecting air resistance

As resistance is absent so Energy at top of hill and at the bottom hill is conserved.

Energy at top is equal to Potential Energy

$E_T=mgh=50\times 9.8\times 184$

Energy at bottom is equal to kinetic energy at bottom

$E_B=\frac{1}{2}mv^2$

$E_T=E_B$

$50\times 9.8\times 184=\frac{1}{2}\times 50\times v^2$

$v=\sqrt{2\times 9.8\times 184}$

$v=60.05\ m/s$

3 0

4 years ago

A 50 kg circus worker stands on a merry go round platform. If the worker's acceleration is 2.5 m/s2, what is her centripetal for

Karolina [17]

F = ma

= 50kg × 2.5 m/s²

= 125 N

Answer : 125N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s²)

5 0

3 years ago

Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen

xxTIMURxx [149]

Answer:

A) first laser

B) 0.08m

C) 0.64m

Explanation:

To find the position of the maximum you use the following formula:

$y=\frac{m\lambda D}{d}$

m: order of the maximum

λ: wavelength

D: distance to the screen = 4.80m

d: distance between slits

A) for the first laser you use:

$y_1=\frac{(1)(d/20)(4.80m)}{d}=0.24m\\$

for the second laser:

$y_2=\frac{(1)(d/15)(4.80m)}{d}=0.32m$

hence, the first maximum of the first laser is closer to the central maximum.

B) The difference between the first maximum:

$\Delta y=y_2-y_1=0.32m-0.24m=0.08m=8cm$

hence, the distance between the first maximum is 0.08m

C) you calculate the second maximum of laser 1:

$y_{m=2}=\frac{(2)(d/20)(4.80m)}{d}=0.48m$

and for the third minimum of laser 2:

$y_{minimum}=\frac{(m+\frac{1}{2})(\lambda)(D)}{d}\\\\y_{m=3}=\frac{(3+\frac{1}{2})(d/15)(4.80m)}{d}=1.12m$

Finally, you take the difference:

$1.12m-0.48m=0.64m$

hence, the distance is 0.64m

3 0

3 years ago