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alina1380 [7]
3 years ago
15

What is the greatest cause for concern regarding hydroelectric power?

Physics
2 answers:
nexus9112 [7]3 years ago
6 0

Answer:

destroys habitats is the main one

Explanation:

eye sore can be one and it can burst causing a flood is also one :)

Harman [31]3 years ago
4 0

Answer:

hydropower facilities can have large environmental impacts by changing the environment and affecting land use, homes, and natural habitats in the dam area.

btw :

stay safe! :3

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An object with an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second squared in the direction
leva [86]

Answer:

6 m/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 4 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =?

The final velocity of the object can obtained as shown below:

v² = u² + 2as

v² = 4² + (2 × 2 × 5)

v² = 16 + 20

v² = 36

Take the square root of both side.

v = √36

v = 6 m/s

Therefore, the final speed of the object is 6 m/s.

8 0
3 years ago
Two ponies of equal mass are initially at diametrically opposite points on the rim of a large horizontal turntable that is turni
AleksandrR [38]

Answer:A

Explanation:

Given

Two ponies are at Extreme end of turntable with mass m

suppose turntable is moving with angular velocity \omega

Moment of inertia of Turntable and two ponies

I=I_o+2mr_0^2

let say at any time t they are at a distance of r from center such r

Moment of inertia at that instant

I'=I_0+2mr'^2

I'

conserving angular momentum as net Torque is zero

I\omega =I'\omega '

\omega '=\frac{I}{I'}\times \omega

\omega '>\omega

Thus we can say that angular velocity increases as they move towards each other.        

3 0
3 years ago
Coulomb's law is expressed mathematically as
nataly862011 [7]
Force between two charges  = 

     ( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²

  in the direction away from each other.

In other words, if the force is positive, the charges are repelling.
If the force is negative, the charges are attracting.
4 0
3 years ago
“Is it correct to say that a radio wave can be considered a low-frequency light wave?
klio [65]

It's weird but technically correct to say that a radio wave can be considered a low-frequency light wave.  Radio and light are both electromagnetic waves.  The only difference is that radio waves have much much much longer wavelengths, and much much much lower frequencies, than light waves have.  But they're both the same physical phenomenon.

However, a radio wave CAN'T also be considered to be a sound wave.  These two things are as different as two waves can be.

-- Radio is an electromagnetic wave. Sound is a mechanical wave.

-- Radio waves travel more than 800 thousand times faster than sound waves do.

-- Radio waves are transverse waves. Sound waves are longitudinal waves.

-- Radio waves can travel through empty space. Sound waves need material stuff to travel through.

-- Radio waves can be detected by radio, TV, and microwave receivers. Sound waves can't.

-- Sound waves can be detected by our ears. Radio waves can't.

-- Sound waves can be generated by talking, or by hitting a frying pan with a spoon. Radio waves can't.

-- Radio waves can be generated by an alternating current flowing through an isolated wire. Sound waves can't.

4 0
4 years ago
You are working at a company that manufactures electri- cal wire. Gold is the most ductile of all metals: it can be stretched in
Alona [7]

Explanation:

We know that the relation between volume and density is as follows.

      Volume = \frac{\text{mass}}{\text{density}}

So,       V = \frac{10^{-3}}{19.3 \times 10^{3} kg/m^{3}}

               = 5.181 \times 10^{-8} m^{3}

Now, we will calculate the area as follows.

      Area = \frac{\text{volume}}{\text{length}}

               = \frac{5.181 \times 10^{-8} m^{3}}{2.4 \times 10^{3}}

               = 2.15 \times 10^{-11} m^{2}

Formula to calculate the resistance is as follows.

         R = \rho \frac{l}{A}

             = \frac{2.44 \times 10^{-8} \times 2400}{}2.15 \times 10^{-11}}

             = 2.71 \times 10^{6} ohm

Thus, we can conclude that the resistance of given wire is 2.71 \times 10^{6} ohm.

4 0
3 years ago
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