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sukhopar [10]
3 years ago
8

Which data set has a greater spread? Why? Set A: {38, 12, 23, 48, 55, 16, 18} Set B: {44, 13, 24, 12, 56} has a greater spread b

ecause .

Mathematics
2 answers:
spayn [35]3 years ago
5 0

Answer:

Set B has a greater spread , because it has a higher IQR

Step-by-step explanation:

One way to measure the spread of a data set is to break it into quarters and measure the interquartile range (IQR).

Set A: {38, 12, 23, 48, 55, 16, 18}

(a) Sort the numbers

(12, 16, 18, 23, 38, 48, 55}

(b) First quartile

The median of 12, 16, and18 is 16.

First quartile = 16

(c) Third quartile

The median of 38, 48, and 55 is 48.

Third quartile = 48

(d) IQR

IQR = 48 - 16  = 32

Set B: {44, 13, 24, 12, 56}

(a) Sort the numbers

(12, 13, 24, 44, 56}

(b) First quartile

The median of 12 and 13 is 12.5.

First quartile = 12.5

(c) Third quartile

The median of 44 and 56  is 50.

Third quartile = 50

(d) IQR

IQR = 50 - 12.5 = 37.5

Set B has the greater spread, because it has the higher IQR.

The Box plot below shows that Set B has the greater spread.

ahrayia [7]3 years ago
4 0

Answer:

Set B has the greater spread

Step-by-step explanation:

Set B has the greater spread because if you add them all up they you will get a number higher than Set A.

Hope this helped :)

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Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
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Answer:

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  • midpoint rule: 14.587831
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Step-by-step explanation:

We assume you want the integral ...

  \displaystyle\int_4^{14}{\sqrt{\ln{x}}}\,dx

The width of each interval is 1/6 of the difference between the limits, so is ...

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Then the point p[n] at the left end of each interval is ...

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<u>Trapezoidal Rule</u>

The area of a trapezoid is the product of its average base length multiplied by the width of the trapezoid. Here, the "bases" are the function values at each end of the interval. The integral according to the trapezoidal rule can be figured as ...

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  integral ≈ 14.559027

If you're doing this on a spreadsheet, you can avoid evaluating the function twice at the same point by using a weighted sum. Weights are 1, 2, 2, ..., 2, 1.

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<u>Midpoint Rule</u>

This rule uses the area of the rectangle whose height is the function value at the midpoint of the interval.

  \dfrac{5}{3}\sum\limits_{n=0}^{5}{f(p[n+\frac{1}{2}])}

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<u>Simpson's Rule</u>

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