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nekit [7.7K]
3 years ago
11

Carla uses a table tennis ball and a volleyball to represent two astronomical bodies based on their sizes. Which of the followin

g representations is the most correct based on what Carla has?
A: The table tennis ball represents the Milky Way and the volleyball represents the local group cluster.
B: The table tennis ball represents the solar system and the volleyball represents Earth.
C: The table tennis ball represents the solar system and the volleyball represents the moon.
D: The table tennis ball represents the Milky Way and the volleyball represents the solar system.
Physics
2 answers:
VladimirAG [237]3 years ago
6 0

Answer:

A: The table tennis ball represents the Milky Way and the volleyball represents the local group cluster.

Explanation:

The universe is huge. It contains millions of billions stars in total of about 10 billion galaxies. These galaxies are grouped into clusters. Milky way is our home galaxy which is part of local group cluster. There are main three galaxies in local group cluster- Milky way, Andromeda and Triangulum. Other than these large galaxies there are dwarf galaxies part of the cluster.

Thus, a table tennis ball which is smaller in size would represent milky way and volley ball would represent local group cluster.

iragen [17]3 years ago
4 0
<span>A: The table tennis ball represents the Milky Way and the volleyball represents the local group cluster.</span>
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Maksim231197 [3]

Answer: 72.66 AU=1.089(10)^{10} km

Explanation:

Let's begin by explaining that according to Kepler’s Third Law of Planetary motion “The square of the orbital period T of a planet is proportional to the cube of the semi-major axis a of its orbit”:

T^{2}\propto a^{3} (1)  

Now, if T is measured in years (Earth years), and a is measured in astronomical units (equivalent to the distance between the Sun and the Earth: 1AU=1.5(10)^{8}km), equation (1) becomes:  

T^{2}=a^{3} (2)  

So, knowing T=619.36 years and isolating a from (2) we have:  

a=\sqrt[3]{T^{2}} (3)  

a=\sqrt[3]{(619.36 years)^{2}} (4)  

Finally:

a=72.66 AU T his is the distance between the dwarf planet and the Sun in astronomical units

Converting this to kilometers, we have:

a=72.66 AU \frac{1.5(10)^{8}km}{1 AU}=1.089(10)^{10} km

4 0
3 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

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3 years ago
Which part of the electromagnetic spectrum have the highest level of photon energy
Pani-rosa [81]
The energy carried by one photon is directly proportional to its
frequency.  So the photon energy is greatest for the electromagnetic
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That's why when you get past visible light and on up through ultraviolet,
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4 0
3 years ago
Vector A⃗ points in the negative y direction and has a magnitude of 5 km. Vector B⃗ has a magnitude of 15 km and points in the p
Alexxandr [17]

Answer:

magnitude of A − B =  15.81 km

Explanation:

Vector A points in the negative y-direction and has a magnitude of 5 km. Vector B points in the positive x-direction and has a  magnitude of 15 km.

According to Cartesian coordinate system, the resultant will start either from tail of A and ends at head of B and vice-versa.

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Magnitude of the vector is given by

|A - B| = \sqrt{(-15)^{2}+(-5)^{2}}

|A - B| = \sqrt{250}

|A - B| = 15.81 km

7 0
3 years ago
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