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Anastasy [175]
3 years ago
6

How many phases does an element have

Chemistry
1 answer:
kogti [31]3 years ago
6 0
Elements have 3 phases
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What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly
Andrej [43]

Answer:

3.65~M

Explanation:

We have to remember the <u>molarity equation</u>:

M=\frac{mol}{L}

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:

100~mL\frac{1~L}{1000~mL}=~0.1~L

Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:

O: 16 g/mol

H: 1 g/mol

C: 12 g/mol

(16*1)+(1*4)+(12*1)=32~g/mol

With the molar mass value we can <u>calculate the number of moles</u>:

1.7~g~of~CH_3OH\frac{1~mol~CH_3OH}{32~g~of~CH_3OH}=0.365~mol~CH_3OH

Finally, we can <u>calculate the molarity</u>:

M=\frac{0.365~mol~CH_3OH}{0.1~L}=3.65~M

I hope it helps!

7 0
3 years ago
How many neutrons make up one of these potassium atoms?
Doss [256]
Potassium has twenty neutrons
6 0
3 years ago
Read 2 more answers
One type of sunburn occurs when skin is exposed
julia-pushkina [17]

Answer:

E = 6.27 × 10⁻²³ Joules

Explanation:

E = h (Plancks constant) × f (frequency)

(Plancks constant = 6.63 × 10⁻³⁴ J×s)

f = λ × c (used to find frequency so you can satisfy energy equation)

*Have to find wavelength in meters to multiply by speed of light*

1. f = (3.15 × 10⁻⁷ m) × (3 × 10⁸ m/s)

2. f = 9.45 × 10¹⁰ s

3. E = (6.63 × 10⁻³⁴ J×s [Plancks constant]) × (9.45 × 10¹⁰ s)

E = 6.27 × 10⁻²³ Joules

8 0
3 years ago
19.The Alkali and Alkaline Earth metals belong to which columns, respectively?
Morgarella [4.7K]

Answer:

i think it is d hope this helps

6 0
3 years ago
An atom of lead has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible unc
victus00 [196]

The question is incomplete. Here is the complete question.

An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x10^{8} m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.

Answer: v% = 0.21 m/s

Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that:  ΔpΔx≥\frac{h}{4\pi }

where h is <u>Planck's constant</u> and it is equal to 6.626.10^{-34}m²kg/s.

Since p (momentum) is p = m.v:

mΔv.Δx ≥ \frac{h}{4\pi }

Δv = \frac{h}{4\pi.x.m }

Given that: r = x = 1.54.10^{-10}m and mass of an electron is m=9.1.10^{-31}kg

Δv = \frac{6.626.10^{-34} }{4.3.14.1.54.10^{-10}.9.1.10^{-31}}

Δv = 0.0376.10^{7}

As percentage of average speed:

Δv.\frac{1}{v}.100% = \frac{0.0376.10^{7} }{1.8.10^{8} }.10² = 0.021.10 = 0.21%

The least possible uncertainty in a speed of an electron is 0.21%.

5 0
4 years ago
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