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fomenos
2 years ago
8

6.

Chemistry
1 answer:
frez [133]2 years ago
4 0

Answer:

Ni^2+

Explanation:

The following data were obtained from the question:

Proton = 28

Electron = 26

Neutron = 34

Next, we shall determine the atomic number of the element.

Atomic number of an element is simply defined as the number of protons in the atom of an element.

Thus,

Atomic number = proton number

Proton = 28

Atomic number = proton number = 28

Atomic number = 28

Therefore, the element is Nickel since no two elements have the same atomic number.

Finally, we shall determine the charge on the Nickel atom as follow:

Proton = 28

Electron = 26

Charge on atom =

Charge on atom = Proton – Electron

Charge on atom = 28 – 26

Charge on atom = +2

Therefore, we can represent the Particle as Ni^2+

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If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--> 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
What ionic bond occurs between what particles?
Sladkaya [172]
B positive and negative ion 
4 0
3 years ago
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
2 years ago
In which of these cases would it be most useful to use a mole to calculate the number of particles?
Ivan
I believe it would be the last one because you can use the molar mass of HCl to find the number of moles, then use Avogadro’s number to find the number of atoms
Hope this helps!
6 0
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viktelen [127]

Answer:

Explanation:

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3 0
3 years ago
Read 2 more answers
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