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slamgirl [31]
3 years ago
11

Household ammonia used for cleaning contains about 10 g (two significant figures) of NH3 in 100 mL (two significant figures) of

solution. What is the molarity of the NH3 in the solution?
Chemistry
1 answer:
lidiya [134]3 years ago
4 0

Answer:

11.44

Explanation:

= Base ionization constant of ammonia =  

m = Mass of ammonia = 5 g

V = Volume of ammonia = 709 mL =  

M = Molar mass of ammonia = 17.03 g/mol

Molaritiy of ammonia

We have the relation

The pH of the solution is 11.44.

Explanation:

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mestny [16]

Answer:

Uses of Sodium chloride:

1.it is used as table salt in our diets

2. it is used as a food preservative

3. It is used as an industrial source of sodium and chlorine

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2. It is used in the manufacture of soap

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1. It is used in the manufacture of detergents and glass

2. It is used to soften hard water

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1. It is used in the manufacture of detergents and glass

2. It is used as a purgative

3. It is used to treat wood-pulp for paper making.

Uses of Potassium nitrate

1. It is used in making gunpowder

2. It is used as rocket propellant

3. It is used in making fertilizer

Uses of Potassium chlorate

1. It is used as an oxidizer

2. It is used in making explosives

3. it is used as a disinfectant

Uses of Potassium permanganate (vii)

1. It is used as an oxidizing agent

2. It is used as a disinfectant

3. It is used as an analytical reagent

Uses of Potassium chloride

1. It is used for the manufacture of fertilizer

2. It is used as an alternative salt to sodium chloride

3. It is used in medicine to treat low blood pressure

2. Potassium nitrate and potassium chloride are used in the manufacture of fertilizers.

Potassium nitrate is used in fertilizers because it provides two important plant nutrients, nitrogen and potassium to plants.

Potassium chloride (potash)  is used in fertilizers because it efficiently deliver the important plant nutrient, potassium, to plants.

Explanation:

Uses of Sodium chloride:

1. it is used as table salt in our diets

2. it is used as a food preservative

3. It is used as an industrial source of sodium and chlorine

Uses of Sodium hydroxide:

1. It is in the laboratory as an alkali in the neutralization of acids

2. It is used in the manufacture of soap

3. It is used in the refining of petroleum

Uses of Sodium carbonate:

1. It is used in the manufacture of detergents and glass

2. It is used to soften hard water

3. it is used to standardize acids in the laboratory

Uses of Sodium sulphate

1. It is used in the manufacture of detergents and glass

2. It is used as a purgative

3. It is used to treat wood-pulp for paper making.

Uses of Potassium nitrate

1. It is used in making gunpowder

2. It is used as rocket propellant

3. It is used in making fertilizer

Uses of Potassium chlorate

1. It is used as an oxidizer

2. It is used in making explosives

3. it is used as a disinfectant

Uses of Potassium permanganate (vii)

1. It is used as an oxidizing agent

2. It is used as a disinfectant

3. It is used as an analytical reagent

Uses of Potassium chloride

1. It is used for the manufacture of fertilizer

2. It is used as an alternative salt to sodium chloride

3. It is used in medicine to treat low blood pressure

2. Potassium nitrate and potassium chloride are used in the manufacture of fertilizers.

Potassium nitrate is used in fertilizers because it provides two important plant nutrients, nitrogen and potassium to plants.

Potassium chloride (potash)  is used in fertilizers because it efficiently deliver the important plant nutrient, potassium, to plants.

4 0
3 years ago
150.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How long will it take
leonid [27]

Given :

Initial mass , a = 150 gm .

Half time ,

t_{\dfrac{1}{2}}=36 \ hours.

Final mass , x = 18.75 gm .

To Find :

The time taken to decay 18.75 gm .

Solution :

We know , time taken is given by :

t=\dfrac{1}{k}\times ln(\dfrac{a}{a-x})

Here , k is a constant given by :

k=\dfrac{0.693}{t_{\dfrac{1}{2}}}\\\\\\k=\dfrac{0.693}{36}

Putting all given value in above equation :

We get :

t=\dfrac{36}{0.693}\times ln(\dfrac{150}{150-18.75})\\\\t=6.94\ hours

Therefore , time taken is 6.94 hours .

Hence , this is the required solution .

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