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Temka [501]
3 years ago
14

You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca

n get the balloon's density below this value, it will float. You measure both the temperature in the room as well as the mass of the balloon you will use and find they are 18.0°C and 0.577 grams, respectively. What volume of balloon will generate a density equal to that of the air around it? (Hint: Use the relationship you calculated above to determine the air density at the temperature given)
Balloon Volume Needed =

equation from problem 1 :y = -0.0043x + 1.2874
Chemistry
1 answer:
asambeis [7]3 years ago
8 0
Answer is: <span>volume of balloon is </span>476,85 cm³.
density of air: d(air) = -0,0043 · 18,0°C + 1,2874.
d(air) = 1,21 kg/m³ = 1,21 · 10³/ 10⁶ = 0,00121 g/cm³.
m(balloon) = 0,577 g.
d(balloon) = d(air).
d(balloon) = m(balloon) ÷ V(balloon).
V(balloon) = m(balloon) ÷ d(balloon)
V(balloon) = 0,577 g ÷ 0,00121 g/cm³.
V(balloon) = 476,85 cm³.
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Given the balanced equation:
Aliun [14]

Answer:

0.4

Explanation:

Given data:

Number of moles of SrCl₂ consumed = ?

Mass of ZnCl₂ produced = 54 g

Solution:

Chemical equation:

ZnSO₄ + SrCl₂    →    SrSO₄ +  ZnCl₂

Number of moles of ZnCl₂:

Number of moles = mass/ molar mass

Number of moles = 54 g/136.3 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of  ZnCl₂ with SrCl₂  from balance chemical equation.

                          ZnCl₂              :             SrCl₂

                              1                  :                1

                           0.4                 :              0.4

Thus when 54 g of  ZnCl₂ produced 0.4 moles of SrCl₂ react.

6 0
3 years ago
If you use about 4.5 x 1023 atoms of carbon in your pencil as you complete this
raketka [301]

Answer:

0.74mol

Explanation:

4.5×10^23/6.02×10^23=0.74mol

3 0
3 years ago
A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure
lord [1]

Answer is:  the absolute pressure of the air in the balloon is 1.015 atm (102.84 kPa).

n = 0.250 mol; amount of substance.

V = 6.23 L; volume of the balloon.

T = 35°C = 308.15 K; temperature.

R = 0.08206 L·atm/mol·K, universal gas constant.

Ideal gas law: p·V = n·R·T.

p = n·R·T / V.

p = 0.250 mol · 0.08206 L·atm/mol·K · 308.15 K / 6.23 L.

p = 1.015 atm; presure of the air.

6 0
3 years ago
a helium balloon has a volume of 2.95 liters at 25 c. the volume of the ballon decreased to 2.25 l after it is placed outside on
OleMash [197]

Answer:

The outside temperature is -45.8°C

Explanation:

When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).

V1 / T1 = V2 / T2

2.95L/298K = 2.25L / T2

(2.95L/298K ) . T2 = 2.25L

T2 = 2.25L . 298K / 2.95L

T2 = 227.2K

T°K - 273 = T°C

227.2K - 273 = -45.8°C

3 0
3 years ago
Which accurately describes nonmetals
Bumek [7]

Answer:

Most nonmetals are solids, but some are gaseous or liquid. All nonmetals are solid unless they bond with a metal.

Explanation:

ANSWER: LOOK IT UP IN YO DICtionary

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8 0
2 years ago
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