Answer: 162.8 grams
Explanation:
Magnesium nitrate has a chemical formula of Mg(NO3)2.
Given that:
Number of moles of Mg(NO3)2 = 1.1 moles
Mass in grams of Mg(NO3)2 = ?
For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g
Mg(NO3)2 = 24g + (14g + 16gx3) x 2
= 24g + (14g + 48g) x 2
= 24g + (62g) x 2
= 24g + 124g
= 148g/mol
Now, apply the formula:
Number of moles = Mass in grams / molar mass
1.1 moles = Mass / 148g/mol
Mass = 1.1 moles x 148g/mol
Mass = 162.8 grams
Thus, there are 162.8 grams of magnesium nitrate.
Answer: 3378.4mL
Explanation:
density of Gasoline = 0.74g/mL.
Volume of gasoline in milliliter = ?
mass of gasoline = 2.5kg
(Since density is in grams per millilitre, convert mass in kilograms to grams)
If 1kg = 1000grams
2.5kg = 2.5 x 1000 = 2500grams
Recall that density is obtained by dividing the mass of a substance by its volume
i.e Density = Mass / Volume
0.74g/mL = 2500grams/Volume
Volume = (2500 grams / 0.74g/mL)
Volume = 3378.4mL
Thus, the volume of gasoline is 3378.4mL
Answer:
B, H, E, G, C, D, A, F
Explanation:
The ones closest to the bottom are the oldest
5.367 ml of the concentrated acid must be added to obtain a total volume of 100 ml of the dilute solution.
Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.
C₁V₁ = C₂V₂
where C₁ = initial concentration of sample = 3.00 m
V₁ = initial volume of sample
C₂ = final concentration after dilution = 0.161 m
V₂ = total final volume after dilution = 100 ml
Plug in the values to the formula and solve for the volume of the concentrated acid that must be added.
C₁V₁ = C₂V₂
3.00 m (V₁) = 0.161 m (100 ml)
V₁ = 5.367 ml
Learn more about dilution here: brainly.com/question/1615979
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