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4 years ago

5

The electric potential difference of a 150 µF capacitor is measured across the terminals of the capacitor and found to be 5 volt

s. What is the potential energy of the capacitor?

2 answers:

Assoli18 [71]4 years ago

7 0

Answer:

it's 2 on edge

Explanation:

Lapatulllka [165]4 years ago

6 0

The potential energy stored in a capacitor is given by:
$U= \frac{1}{2}CV^2$
where
C is the capacitance of the capacitor
V is the potential difference across the plates of the capacitor

In our problem,
$C=150 \mu F= 150 \cdot 10^{-6} F$
$V=5 V$
Therefore, the potential energy of the capacitor is
$U= \frac{1}{2}(150 \cdot 10^{-6}F)(5 V)^2 = 1.88 \cdot 10^{-3}J$

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Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would

Tatiana [17]

Answer:

<h3>The power of headlight in series connection is 29.64 W</h3>

Explanation:

Given :

Power of headlight $P_{1} = 30$ W

Power of starter $P_{2} = 2500$ W

Voltage of headlight and starter $V = 12$ V

From equation of power,

$P = \frac{V^{2} }{R}$

$R = \frac{V^{2} }{P}$

For finding the resistance of headlight and starter,

⇒ For headlight,

$R_{1} = \frac{144}{30} = 4.8$ Ω

⇒ For starter,

$R_{2} = \frac{144}{2500} = 0.057$ Ω

Since equivalent resistance,

$R_{eq} = R_{1} + R_{2} + ........$

$R_{eq} = 4.8 +0.057 = 4.857$ Ω

So power in series is given by,

$P_{s } = \frac{V^{2} }{R_{eq} } = \frac{144}{4.857}$

$P_{s } = 29.64$ W

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4 years ago

Why do astronomers think that the milky way is a spiral galaxy?

Nikolay [14]

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3 years ago

Taste and smell are called chemical senses because:

Bingel [31]

Answer:

The answer is a," their receptors are sensitive to chemical molecules."

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4 years ago

A sun-like star is barely visible to naked-eye observers on earth when it is a distance of 7.0 light years, or 6.6 * 1016 m, awa

igomit [66]

Answer:

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Explanation:

Distance between Sun and earth $6.6\times 10^{16}m$

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Power emitted by candle = 0.20 watt

We know that brightness is given by

$B=\frac{P}{4\pi d^2}$

So $\frac{3.8\times 10^{26}}{4\pi (6\times 10^{16})^2}=\frac{0.20}{4\pi d^2}$

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3 0

3 years ago

DochEvi [55]

Answer:

3.83×10⁻¹⁹ J

Explanation:

The energy of a photon can be found using the formula: E=hc/λ

h is Planck's Constant which is approximately 6.63×10⁻³⁴
c is the speed of light which we'll round to 3.00×10⁸
λ is the wavelength of the photon. You typed 5200 but that's not even within the visible light spectrum's wavelength range, so I'm going to assume you meant 520 nm; or 5.20×10⁻⁷ m.

Plugging all that info in should give approximately 3.83×10⁻¹⁹ Joules of energy.

(You could get slight variations depending on what you chose to round up or down or not at all.)

5 0

3 years ago