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My name is Ann [436]
3 years ago
5

The unit of electrical current is the ampere (A).

Physics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

option B

Explanation:

Current unit is ampere (A)

Ampere will be equivalent to = ?

we know,

Current can be define as the charge per unit time

I = \dfrac{Q}{t}

unit of charge(Q) is coulomb which is equal to C.

unit of time(t) is equal to 's'.

now,

I = \dfrac{C}{s}

unit of I = C/s

ampere(A) is equivalent to C/s

The correct answer is option B

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Power used by the clock=1.03 W

Explanation:

resistance= 14000 ohm

voltage=120 V

The formula for the power is given by

P=\frac{V^{2}}{R}

P=(120)²/14000

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Answer:

25cm^2

Explanation:

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Answer:

A)  350 N

B)  58.33 N

C)  35 kg

D)  35 kg

Explanation:

If we use that g = 10 m/s^2, then the acceleration of gravity on the Moon will be 10/6 m/s^2 = 5/3 m/s*2

The weight of the object on Earth is given by:

Weight = mass * g = 35 * 10 = 350 N

The weight of the object on the Moon:

Weight = mass * gmoon = 35 * 5/3 = 58.33 N

The mass of the object on Earth is 35 kg

The mass of the object on the Moon is exactly the same as on the Earth (35 kg) since the mass is a quantity inherent to the object and not to its location.

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Which of the following forms matter?<br> A. Proteins<br> B.atoms<br> C.cells<br> D. DNA
Artemon [7]

Answer:b) atoms

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Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzz
amid [387]

Answer:

(C) The frequency decrease and intensity decrease

Explanation:

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if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.

The frequency is the inverse from the wavelength, so the frequency heard will increase.

The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.

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