All categories

3 years ago

Please help me on this question

Physics

1 answer:

soldi70 [24.7K]3 years ago

3 0

Lowest -- 1

Next -- 4

Next -- 2

Highest -- 3

If every resistor is, let's say, 100 ohms, then . . .

#1 ... 25 ohms

#2 ... 250 ohms

#3 ... 400 ohms

#4 ... 100 ohms

You might be interested in

What happens to the mass and to the weight of the foam rubber when it is compressed?

Orlov [11]

Answer:

423523523523

Explanation:

52334W53WR53WRRWRW35423

4 0

2 years ago

Read 2 more answers

The strength of the electric field of a charged particle becomes greater as the distance from the particle increases. T F

natali 33 [55]

The answer is T it is true

7 0

3 years ago

Help plz. Even when you're not moving, your body needs energy for functions such as breathing, circulating blood and repairing c

KatRina [158]

<u>ANSWER</u>

metabolism

I really hope this helps i am in middle school and this must be a high school question.

4 0

3 years ago

1. If the angle of the ramp were increased from 30˙ to 45˙, how would this change the weight of the box? Explain.

yawa3891 [41]

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

<h3>Normal reaction of the box</h3>

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

<h3>when the angle of the ramp = 30⁰</h3>

Fn = Wcos(30)

Fn = 0.866W

<h3>when the angle of the ramp = 45⁰</h3>

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

Learn more about normal reaction here: brainly.com/question/18292235

#SPJ1

4 0

2 years ago

Consider a series LRC-circuit in which C-120.0 uF. When driven at a frequency w = 200.0 rad s-1 the com ples impedance is given

Lina20 [59]

Answer:

(a). (i). The reactants are $X_{L} =31.66\ \Omega$ .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

Explanation:

Given that,

Capacitor = 120.0 μC

Frequency = 200.0 rad/s

Impedance = 100.0 -10j

(I). We need to calculate the $X_{C}$

$X_{C}=\dfrac{1}{C\times\omega}$

Put the value into the formula

$X_{C}=\dfrac{1}{120\times10^{-6}\times200}$

$X_{C}=41.66\ \Omega$

(II). We know that,

Formula of impedance is

$Z=\sqrt{R^2+X_{L}^2+X_{C}^2}$ ...(I)

Given equation of impedance is

$Z=(100-10j)$ ...(II)

On Comparing of equation (I) and (II)

$R = 100$

$X_{L}-X_{C}=-10$

Now, put the value of $X_{C}$

$X_{L=41.66-10$

$X_{L}=31.66\ \Omega$

We need to calculate the inductance

Using formula of inductance

$X_{L}=\omega\times L$

Put the value into the formula

$L=\dfrac{X_{L}}{\omega}$

$L=\dfrac{31.66}{200}$

$L=0.1583\ Henry$

(b). We need to calculate the resonant angular frequency

Using formula of the resonant angular frequency

$angular\ frequency =\dfrac{1}{\sqrt{L\times C}}$

$angular\ frequency =\dfrac{1}{\sqrt{0.1583\times120\times10^{-6}}}$

$angular\ frequency =229.4\ rad/s$

Hence, (a). (i). The reactants are $X_{L} =31.66\ \Omega$ .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

4 0

3 years ago

Please help me on this question​

Please help me on this question