$(0,,386. Sup apt g 9=6 ♂️
Answer:
d=1.25 m
Explanation:
fd=.5mv2-.5mv1; 10(d)=.5(50)(.5)-0; 10(d)=12.5; d=12.5/10; d=1.25 m
Answer:
Explanation:
Distance traveled by light = 2 x 550 m = 1100 m
time taken by light to travel this distance = 1100 / 3 x 10⁸
= 366.67 x 10⁻⁸ s
angle between two consecutive slots = 2π / 500 rad
= .004π
angular velocity of wheel = angle moved / time taken
= .004π / 366.67 x 10⁻⁸
= 1091π radian / s
b ) linear speed of a point on the edge of the wheel
= ω R , r is radius of wheel , ω is angular velocity.
= 1091π x 5 x 10⁻²
= 1712.8 m /s
The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:

We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11