The elastic potential energy increases by a factor of 9
Explanation:
The elastic potential energy of a bowstring is given by
(1)
where
k is the spring constant
x is the elongation of the bowstring
Hooke's law states the relationship between the force applied and the elongation of an elastic object:
where
F is the force applied
x is the elongation
We can rewrite it as
And substituting into (1),
In this problem, the force applied to the bowstring is tripled,
F' = 3F
So the final elastic potential energy is:
So, the elastic potential energy increases by a factor of 9.
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The speed of sound at 46 C is 800.91 mph
Answer:
23 mi
Explanation:
Let us first record all the values we have
acceleration = 4 ft/s
max speed = 90 mi/hr * 1 hr/3600s * 5280 ft/1 mi = 132 ft/s
We can use the equation of linear motion since acceleration is constant
distance covered = distance during acceleration + distance during costant
velocity
distance in miles = 120 978 ft * 1 mi/5280 ft = 22.9125 mi ≈ 23 mi
Answer:
The SI unit of current is ampere which measures the flow of electric charge across a surface at the rate of one coulomb per second.
