What is the frequency if a wave that pases a given pount 22 times in 2 seconds

A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of

Gennadij [26K]

To solve this problem we will apply the concepts related to the electric field such as the smelting of the Force and the load (In this case the force is equivalent to the weight). Later we will apply the ratio of the total charge as a function of the multiplication of the number of electrons and their individual charge.

$E = \frac{mg}{q}$

Here,

m = mass

g = Acceleration due to gravity

Rearranging to find the charge,

$q = \frac{mg}{E}$

Replacing,

$q = \frac{(3.37*10^{-9})(9.8)}{11000}$

$q = 3.002*10^{-12}C$

Since the field is acting upwards the charge on the drop should be negative to balance it in air. The equation to find the number of electrons then is

$q = ne$

Here,

n = Number of electrons

e = Charge of each electron

$n = \frac{q}{e}$

Replacing,

$n = \frac{3.002*10^{-12}}{1.6*10^{-19}}$

$n = 2.44*10^7$

Therefore the number of electrons that reside on the drop is $2.44*10^7$

5 0

4 years ago

A very narrow beam of white light is incident at 40.80° onto the top surface of a rectangular block of flint glass 11.6 cm thick

DerKrebs [107]

Dispersion angle = 0.3875 degrees.
Width at bottom of block = 0.09297 cm
Thickness of rainbow = 0.07038 cm
Snell's law provides the formula that describes the refraction of light. It is:
n1*sin(Î¸1) = n2*sin(Î¸2)
where
n1, n2 = indexes of refraction for the different mediums
Î¸1, Î¸2 = angle of incident rays as measured from the normal to the surface.
Solving for Î¸2, we get
n1*sin(Î¸1) = n2*sin(Î¸2)
n1*sin(Î¸1)/n2 = sin(Î¸2)
asin(n1*sin(Î¸1)/n2) = Î¸2
The index of refraction for air is 1.00029, So let's first calculate the angles of the red and violet rays.
Red:
asin(n1*sin(Î¸1)/n2) = Î¸2
asin(1.00029*sin(40.80)/1.641) = Î¸2
asin(1.00029*0.653420604/1.641) = Î¸2
asin(0.398299876) = Î¸2
23.47193844 = Î¸2
Violet:
asin(n1*sin(Î¸1)/n2) = Î¸2
asin(1.00029*sin(40.80)/1.667) = Î¸2
asin(1.00029*0.653420604/1.667) = Î¸2
asin(0.39208764) = Î¸2
23.08446098 = Î¸2
So the dispersion angle is:
23.47193844 - 23.08446098 = 0.38747746 degrees.
Now to determine the width of the beam at the bottom of the glass block, we need to calculate the difference in the length of the opposite side of two right triangles. Both triangles will have a height of 11.6 cm and one of them will have an angle of 23.47193844 degrees, while the other will have an angle of 23.08446098 degrees. The idea trig function to use will be tangent, where
tan(Î¸) = X/11.6
11.6*tan(Î¸) = X
So for Red:
11.6*tan(Î¸) = X
11.6*tan(23.47193844) = X
11.6*0.434230136 = X
5.037069579 = X
And violet:
11.6*tan(Î¸) = X
11.6*tan(23.08446098) = X
11.6*0.426215635 = X
4.944101361 = X
So the width as measured from the bottom of the block is: 5.037069579 cm - 4.944101361 cm = 0.092968218 cm
The actual width of the beam after it exits the flint glass block will be thinner. The beam will exit at an angle of 40.80 degrees and we need to calculate the length of the sides of a 40.80/49.20/90 right triangle. If you draw the beams, you'll realize that:
cos(Î¸) = X/0.092968218
0.092968218*cos(Î¸) = X
0.092968218*cos(40.80) = X
0.092968218*0.756995056 = X
0.070376481 = X
So the distance between the red and violet rays is 0.07038 cm.

7 0

3 years ago

an airplane is taking off from an airport with velocity of 200 km/h at an angle of 30 degrees above horizontal how fast is its r

ddd [48]

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7 0

3 years ago

What is the primary difference between an ideal emf device and a real emf device?.

EleoNora [17]

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

3 0

2 years ago

Read 2 more answers

Sort the length measurements in increasing order of magnitude from smallest to largest Drag each tile to the correct box Tiles S

wariber [46]

Answer:

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Explanation:

Given the following length measurement :

micrometer Kilometer decimeter centimeter nanometer dekameter.

Sorting in increasing order of magnitude from Smallest to Largest.

Expressing in terms of meters :

1 meter = 0.1 decameter

1 meter = 1 × 10^9 nanometer

1 meter = 1 × 10^2 centimeter

1 meter = 1 × 10^1 decimeter

1 meter = 0.001 kilometer

1 meter = 1 × 10^6 micrometers

Hence, arranging from Smallest to Largest :

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

3 0

4 years ago