Explanation:
Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.
It is known that at standard condition, vapor pressure is 760 mm Hg.
And, it is given that methanol vapor pressure in air is 88.5 mm Hg.
Hence, calculate the volume percentage as follows.
Volume percentage = 
= 
= 11.65%
Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.
I believe the answer would be A. Electronegativity increases across a period.
Mr: 207.2
m=n×Mr= 6.53×207.2= 1353.02g
Ah is gold and Rh is rhodium and Os is osmium and Ir iridium