Answer:
67.492cm^3
Explanation:
To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.
We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.
The volume of the substance is simply the mass of the substance divided by the density of the substance.
This is thus volume = mass/density
The mass given is the question is 60g while the density given is 0.889g/cm^3
The volume = 60/0.889 = 67.492cm^3
There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In
, the valancy of Fe is +2 .
2 moles of
are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of
are required for the decomposition of 0.128 mole of Fe .
moles of
are required = 0.256 moles
Charge on 1 mole of
= 96500 C
Charge on 0.256 mole of
= 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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You just need the number of protons and number of neutrons as the mass of eelctrons is negligible
Answer:
785
Explanation:
Molecular. X. W
Weight
8000-16000 0.05 0.03
16000-24000. 0.017. 0.08
24000-32000. 0.22. 0.18
32000-40000. 0.25. 0.35
40000-48000. 0.22. 0.27
48000-56000. 0.09. 0.09
Mean weight X*M. W*M
12000. 600. 240
20000. 3200. 2000
28000. 6720. 5600
36000. 10080. 10800
44000. 8800. 11880
52000. 3640 3640
Total=33040g\mol 36240
Note before repeat molecular weight m= 3*12.01+6*1.008=
42.08g/mol
Degree of polymerization= total W*M/w=33040/42.08 =785