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Aleks04 [339]
3 years ago
5

What is the quotient (x3 8) ÷ (x 2)?

Mathematics
2 answers:
Tanya [424]3 years ago
8 0
If you would like to solve (x^3 + 8) / (x + 2), you can do this using the following steps:

x^3 + 8 = (x + 2) * (x^2 - 2x + 4)

(x^3 + 8) / (x + 2) = (x + 2) * (x^2 - 2x + 4) / (x + 2) = <span>x^2 - 2x + 4
</span>
The correct result would be <span>x^2 - 2x + 4.</span>
Musya8 [376]3 years ago
7 0

As the Question is not clear

But there are two possibilities

1. \frac{x^3+8}{x+2}=\frac{(x+2)(x^2-2 x+4)}{x+2}=x^2-2 x+4→→Cancelling x+2 from numerator and denominator

→→ Using the formula (a³ + b³) =(a+b)(a² - ab + b²)

Or if

\frac{x^3-8}{x-2}=\frac{(x-2)(x^2+2x+4)}{x-2}=x^2+ 2 x +4→→Cancelling x-2 from numerator and denominator

Using the formula (a³ - b³) =(a-b)(a² + ab + b²)

Statement (1) appears true.

So, correct option is  x²- 2 x + 4 or x² + 2 x + 4

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A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme
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The inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140

<h3>Part A: The inequality</h3>

Let the temperature of the gas be represented with x.

When the temperature hits −40° F (or below), the gas freezes.

This means that the gas temperature must always exceed −40° F to remain being a liquid

i.e x > −40

Also, when the temperature hits 140° F (or above), the gas evaporates.

This means that the gas temperature must always be less than 140° F to remain being a liquid

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So, we have:

x > −40 and x < 140

Rewrite as:

-40 < x and x < 140

Combine both inequalities

-40 < x < 140

Hence, the inequality to represent the temperatures at which the gas in the truck will remain in liquid form is -40 < x < 140

<h3>Part B: The description of the graph</h3>

In (a), we have:

-40 < x < 140

The end points of the inequalities use a less than sign.

Less than signs are represented by open circle.

Hence, the graph would use an open circle, and intervals between -40 and 140 would be shaded

<h3>Part C: Would −49° F gas remained in liquid form?</h3>

We have:

-40 < x < 140

The number -49 is not in the range -40 < x < 140

Hence, the gas would not remain in liquid form (in fact, it would freeze because it is less than -40)

Read more about inequalities at:

brainly.com/question/24372553

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